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GenaCL600
7 days ago
11

Suppose that, for every lot of 100 computer chips a company produces, an average of 1.4 are defective. Another company buys many

lots of these chips at a time, from which one lot is selected randomly and tested for defects. If the tested lot contains more than three defects, the buyer will reject all the lots sent in that batch. What is the probability that the buyer will accept the lots?Assume that the defects per lot are Poisson distributed.Round your answer to 4 decimal places.The tolerance is +/- 0.0005.
Mathematics
1 answer:
babunello [3.6K]7 days ago
7 0

Answer:

0.1665

Step-by-step explanation:

It is known that there is an average of 1.4 defects for every 100 computer chips produced.

Should a tested batch reveal more than three defects, the entire shipment associated with that batch will be rejected by the buyer.

Let X represent the count of defective pieces in a sample of 100 chips.

X follows a Poisson distribution with a mean of 1.4.

Therefore, the probability for the buyer to accept the shipments is calculated as:

=P(X\geq 3)\\\\=0.16651

The final answer is 0.1665

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