Lin made a mixture consisting of 24 ounces of instant tea and 12 ounces of green tea. Approximately how many milligrams of caffe

We can simplify by reducing factors between the 5 and the 50, as well as between the 42 and the 3.

Given:

The temperature recorded at 10:00 am is 8 degrees Fahrenheit.

The temperature decreases by 3 degrees Fahrenheit each hour.

To find:

The temperature at 2:00 pm on the same day.

Solution:

Let y represent the temperature after x hours since 10:00 am.

The temperature at 10:00 am serves as the initial temperature.

Thus, the y-intercept of the linear equation is 8.

The temperature reduces by 3 degrees Fahrenheit every hour.

This indicates the slope of the linear equation is -3, with the negative sign indicating a decrease.

The slope-intercept form of a linear function is indicated by

where m is the slope and b is the y-intercept.

Inserting m=-3 and y=8 into the above equation gives us the required values.

From 10:00 am to 2:00 pm spans 4 hours; therefore, substitute x=4 into the above equation.

Consequently, the temperature at 2:00 pm is -4 degrees Fahrenheit.

n equals 277

9 multiplied by 27 plus 2 multiplied by 31 minus 28 gives n

243 plus 62 minus 28 results in n

305 minus 28 equals n

which means 277 is n

Response: The properties of mathematical operations assist in solving integer-related problems as they provide various methods to arrive at the solution.

Step-by-step explanation:

Answer:

45 millas.

Explicación paso a paso:

Dado que la:

Distancia total recorrida = 390 millas

Tiempo total = 8 horas

Designando la distancia recorrida por la vía local como L

y la distancia recorrida por la carretera como H

Por la vía local,

La Velocidad = distancia/ tiempo

20 = L / T

T = L /20.... (1)

Por la carretera,

Distancia recorrida H = 390 - L

Sea el tiempo = t

La Velocidad = distancia/tiempo

60 = (390 - L)/t

t = ( 390 - L)/60

Pero el tiempo total = T + t

<pEs decir

8 = L/20 + (390 - L)/60

<pEl MCM en el lado derecho sería 60<p8 = ( 3L + 390 - L )/60<pMultiplicamos en cruz

480 = 2L + 390

<pAgrupamos los términos semejantes

2L = 480 - 390

2L = 90

L = 90/2

L = 45 millas.

<pAsí que la distancia que Minato recorrió por vías locales es de 45 millas