Response:
6.48
Detailed explanation:
The calculation required to determine the number of tiles for the border is presented below:-
Here,
The length measures 2.02 m
And the width is 1.22
Substituting these dimensions into the formula provided above
Consequently, the total number of tiles necessary to create the border is
= 6.48
Hence, to find the tiles required for the border, we utilized the aforementioned formula.
Respuesta:
1/16 2/16 3/16 4/16 5/16 6/16 7/16 8/16 9/16 10/16 11/16 12/16
Explicación paso a paso:
Para identificar las brocas existen dos aspectos a considerar:
1.- Las fracciones que comparten el mismo denominador aumentan en orden ascendente a medida que los numeradores incrementan, lo que significa que entre
9/16 3/16 7/16 5/16 11/16 el orden sería (de menor a mayor)
3/16 5/16 7/16 9/16 11/16
2.- Fracciones con diferentes denominadores pueden convertirse a un denominador común /16 multiplicando la fracción, por ejemplo
1/4 = 1*4/4*4 = 4/16
Aplicando este método, todas las fracciones se transforman al formato mencionado previamente y se organizan
1/4 = 4/16
3/8 = 6/16
1/2 = 8/16
5/8 = 10/16
1/8 = 2/16
Por lo tanto, hay diez brocas, comenzando con 1/16 hasta la número 12 que es 12/16
Finalmente, el orden sería:
1/16 2/16 3/16 4/16 5/16 6/16 7/16 8/16 9/16 10/16 11/16 12/16
Response:
Step-by-step breakdown:
Kevin has already gathered five and a half gallons of water for his trip
He understands that he requires a minimum of 20 gallons of water for the journey.
The water is packaged in 32-fluid ounce (quarter-gallon) containers.
1 fluid ounce equals 0.0078125 gallons
32-fluid ounce 
Let x represent the number of 32-fluid ounce (quarter-gallon) containers needed to collect at least 20 gallons of water for the trip.
One container holds 0.25 gallons of water
Therefore, x containers hold 0.25x gallons of water
Thus, Kevin's total gallons of water =
Since it is given that he needs at least 20 gallons of water for the trip.
Hence,
Thus, the algebraic inequality representing this scenario is
Answer:
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in the reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
Step-by-step explanation:
A frog positioned right at the center of a 5ft long board is 2.5 ft away from either edge.
Every 10 seconds, the frog jumps left or right.
If the frog's jumps are LLRLRL, it will remain on the board at the leftmost square.
If it jumps as LLRLL, it will jump off the board after fifty seconds.
Given that the frog jumps every 10 seconds
(using digits from a random number table)
- It requires 7 jumps with 2 in reverse direction (either left or right) for the frog to get off the board in 60 seconds.
- Alternatively, 3 jumps in the same direction will also lead to the frog being off the board.
- Furthermore, it would take 5 jumps with one in the opposite direction within the time limit of 60 seconds to leave the board.
