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atroni
4 days ago
8

The cost of soup, s, varies directly with the number of cans, c. When c is 4, the cost is $3. Which graph represents the cost of

the soup?

Mathematics
2 answers:
AnnZ [3.8K]4 days ago
4 0

It is understood that

A direct variation exists between two variables, x and y, if it can be represented as

\frac{y}{x} =k\ or\ y=kx

In this particular scenario

Define

x--------> the count of cans

y-------> the expense of a soup

therefore

when

x=4\ cans\\y=\$3

substituting

\frac{y}{x} =k\\\\ \frac{3}{4} =k

the resulting equation is

y=\frac{3}{4}x

by utilizing a graphing tool

refer to the figure attached

the solution is depicted in the attached figure

babunello [3.6K]3 days ago
4 0

Response:

The correct answer is C on Edg2020

Detailed explanation:

I hope this is useful!!! Wishing you a wonderful day!!!: )

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Answer:

dV(t)/dt = kV(t)

Step-by-step explanation:

The annual change in the car's value, represented by dV(t)/dt, has a proportional relationship with V(t), the car's current value.

dV(t)/dt ∝ V(t)

dV(t)/dt = kV(t)

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You have a stack of pennies without counting the pennies, how can you know if there is a odd or even number of them
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Imagine having a pile of pennies and you want to determine if the count is odd or even without tallying them one by one. You can separate them into pairs by placing one coin in the left pile and one in the right.

If no coin is left unmatched, then the total number is even; if there is one coin remaining unpaired, the number is odd.

 

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13 days ago
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Thirty-four college students were asked how much money they spent on textbooks for the current semester. Their responses are sho
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Answer:

(a) The data point that is considered an outlier is $810.

(b) The distribution regarding expenditures on textbooks among the 34 students is right skewed.

Step-by-step explanation:

The provided data regarding how much 34 college students spent on textbooks is:

S = {120, 130, 130, 140, 150, 150, 160, 170, 180, 210, 220, 230, 240, 250, 260, 280, 280, 290, 290, 290, 310, 320, 320, 370, 380, 390, 410, 440, 450, 470, 510, 530, 620, 810}

(a)

An outlier is defined as a value significantly different from the rest of the dataset, being either excessively high or low.

A widely-used approach for identifying outliers involves:

  • Identifying values that fall below Q₁ - 1.5 IQR as outliers.
  • Identifying values that exceed Q₃ + 1.5 IQR as outliers.

In our case,

Q₁ = first quartile

Q₃ = third quartile

IQR = Interquartile range = Q₃ - Q₁.

The first quartile value corresponds to more than 25% of the data points. It can be found by examining the median of the first half of the data.

Calculate the first quartile with the set below:

Initial half of data: {120, 130, 130, 140, 150, 150, 160, 170, 180, 210, 220, 230, 240, 250, 260, 280, 280}

This subset contains 17 values.

The median in an odd-sized dataset is the central point.

The central value here is: 180

Thus, the first quartile is Q₁ = 180.

The third quartile value corresponds to more than 75% of the data points.

We determine the third quartile from the second half of the data:

Final half of data: {290, 290, 290, 310, 320, 320, 370, 380, 390, 410, 440, 450, 470, 510, 530, 620, 810}

<pthis subset="" also="" consists="" of="" values.="">

The median of an odd dataset serves as the middle value.

The central point is: 390

Hence, the third quartile is Q₃ = 390.

Calculate the interquartile range as follows:

IQR = Q₃ - Q₁

      = 390 - 180

      = 210

Next, we compute the value of [Q₁ - 1.5 IQR]:

Q_{1}-1.5\ IQR =180-(1.5\times 210)=-135

And then we compute [Q₃ + 1.5 IQR]:

Q_{3}+1.5\ IQR =390+(1.5\times 210)=705

There are no values below [Q₁ - 1.5 IQR]. However, one value exceeds [Q₃ + 1.5 IQR].

X = 810 > [Q₃ + 1.5 IQR] = 705

Consequently, the outlier identified within the dataset is $810.

(b)

A distribution is classified as positively skewed or right-skewed when the majority of the data congregates on the lower end of the spectrum.

The stem plot indicates that most of the data values are concentrated on the left side, confirming that the distribution is indeed right skewed.

</pthis>
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