The graphs below show measurements from cubes with different side lengths. Which pairs of variables have a linear relationship?

Answer: The correct choice is (C) A = {1, 2, 3, 4, 5, 7, 8}.

Step-by-step explanation: We have eight identical slips of paper, each numbered from one to eight, which have been mixed inside a bag.

The sample space, S is as follows:

S = {1, 2, 3, 4, 5, 6, 7, 8}.

Subset A consists of the complement of the event where the number 6 is drawn.

Let 'B' denote the event of drawing the number 6.

Thus, B = {6}.

Since 'A' represents the complement of 'B', it will include all elements in the sample space 'S' that are not part of set 'B'.

Therefore,

A = B' = {1, 2, 3, 4, 5, 7, 8}

So, A = {1, 2, 3, 4, 5, 7, 8}.

Consequently, (C) is the correct choice.

Answer: The cube root of 10 is 2.1544, using an initial value of -0.003723.

Step-by-step explanation: The Newton-Raphson method is utilized for root finding, and its formula is NR: X=Xo-(f(x)/f'(x)). Before applying this formula, the derivative of the equation must be determined. Given that X =10, this method was implemented to identify the best root to ascertain the cube root of 10 to 5 significant figures. Utilizing software like Excel for quicker iteration calculations is advisable. The found root in this instance was -0.003723.

Organizing the data in increasing order to find the outlier and compute the mean

Detailed explanation:

The provided data consists of: [4, 1, 3, 10, 18, 12, 9, 4, 15, 16, 32]

Arranging it in ascending sequence

                               [1, 3, 4, 4, 9, 10, 12, 15, 16, 18, 32 ]

The outlier is identified as 32

Calculating the mean;

Mean=total of data set/quantity of data set

Total= 1 + 3+ 4+ 4+ 9+ 10+ 12+ 15+ 16+ 18+ 32=124

Quantity of data set=11

Mean=124/11=11.27

<span>The distribution of a data set is indicated by the standard deviation, and the range can serve as an estimate for this characteristic. Consequently, Set b (100, 140, 150, 160, 200, 10, 50, 60, 70, 110) exhibits the greatest standard deviation due to its 190 range (i.e., 200 - 10).</span>

Answer:

35.7 km and 248.3 °

Step-by-step explanation:

To clarify, I will include a diagram as an image.

We begin with the cosine law formula:

y² = 42² + 28² - (2 * 42 * 25 * cos 58 °)

y² = 2389 - 1112.83 = 1276.17

y = √1276.17

y = 35.72 km

Next, to find the bearing of the surveyor from her camp, we apply the sine law:

[(Sin 58 °) / y] = [(Sin A) / 42]

Here, A = (42 * sin 58 °) / 35.72

A = sin⁻¹ (0.9971)

A = 85.7 °

The bearing from the base camp now calculates to: 270 ° - (85.7 ° - 64 °) = 248.3 °