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Travka
2 months ago
8

When benzene (c6h6) reacts with bromine (br2) bromobenzene(c6h5br) is obtained: c6h6 + br2 → c6h5br + hbr what is the theoretica

l yield of bromobenzene in this reaction when 30.0g of benzene reacts with 65.0 g of bromine?
b. if the actual yield of bromobenzene was 56.7 g what was the percentage yield?
Chemistry
1 answer:
Anarel [2.9K]2 months ago
3 0

Answer A): First, find the number of moles of benzene used:

30 g divided by the molar mass of benzene (78 g/mol) equals 0.384 moles


For bromine, calculate similarly:

65 g divided by its molar mass (159.8 g/mol) equals 0.406 moles


The balanced reaction shows a 1:1 molar ratio between bromine and benzene.


Calculate the molar mass of bromobenzene:

6 carbons × 12 + 5 hydrogens × 1 + bromine (79.90) = 156.9 g/mol


The mass of bromobenzene formed equals 156.9 g/mol × 0.3846 mol = 60.343 g


Thus, the theoretical yield is 60.34 g.


Answer B): The percent yield is found by dividing the actual yield by the theoretical yield and multiplying by 100%:


(56.7 g ÷ 60.343 g) × 100% = 93.96%


This means the reaction achieved a 93.96% yield, acknowledging that 100% yield is unattainable in chemical reactions.

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Answer:

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I hope this is helpful!

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