Answer:
K2X
Explanation:
The term valency refers to an element's capacity to combine with other elements. This property determines how an element is represented in a chemical compound's formula.
For magnesium and element X, represented as MgX, magnesium typically has a valency of +2 in its compounds. The absence of the +2 in the formula implies that element X must possess a -2 valency, resulting in a cancellation of the valencies.
Furthermore, potassium is classified as an alkaline metal in group 1 of the periodic table, leading to an expected valency of +1.
When forming a compound with element X, a valency exchange occurs. Since X has a -2 valency, the resulting formula of the compound formed by the exchange will be K2X.
Context:
175 kilograms of methane (CH4) is to be converted into hydrogen cyanide (HCN)
The equation that balances this reaction is listed here:
2 CH4<span> + 2 NH</span>3<span> + 3 O</span>2<span> → 2 HCN + 6 H</span>2<span>O
</span>
To find the quantities of ammonia and oxygen needed, we will use 175 kg of CH4 as our reference.
Molar masses are as follows:
CH4 = 16 kg/kmol
NH3 = 17 kg/kmol
O2 = 32 kg/kmol
For ammonia: mass of NH3 = 175 kg CH4 / 16 kg/kmol * (2/2) * 17 kg/kmol
This results in 185.94 kg of NH3 required
For oxygen: mass of O2 = 175 kg CH4 / 16 kg/kmol * (3/2) * 32 kg/kmol
So the mass of O2 needed equals 525 kg
To derive the mass of oxygen: mass of O = 525 kg / 32 kg/kmol * (1/2) * 16 kg/kmol
This gives a mass of O equal to 131.25 kg O
<span>BaCl2 + Na2SO4 --> BaSO4 + 2NaCl
In this reaction, 1.0 g of BaCl2 and 1.0 g of Na2SO4 are present. We need to identify the limiting reactant.
"First, convert grams to moles"
1.0 g BaCl2 * (1 mol BaCl2 / 208.2 g BaCl2) = 4.8 x 10^-3 mol BaCl2
1.0 g Na2SO4 * (1 mol Na2SO4 / 142.04 g Na2SO4) = 7.0 x 10^-3 mol Na2SO4
(7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2) = 1.5 mol Na2SO4 per mol BaCl2
"Using this ratio to compare with the balanced equation, BaCl2 + Na2SO4 --> BaSO4 + 2NaCl"
The balanced equation indicates that 1 mol of BaCl2 reacts with 1 mol of Na2SO4. However, we found that 1.5 mol of Na2SO4 is available for each mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>
Answer:
Explanation:
The percent composition indicates the mass percentage of a specific element within the compound.
The chemical formula for chromium(III) nitrate is 
.
The molar mass for chromium(III) nitrate is calculated at 238.011 g/mol.
Each mole of chromium(III) nitrate includes 9 moles of oxygen.
The molar mass of oxygen is 16 g/mol.
Hence, Mass = Molar mass * Moles = 16 * 9 g = 144 g.
Answer:
B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]
Explanation:
For the reaction A + B → C
The expression for the reaction's rate is:
Δ[C]/Δt = k [A] [B]
Utilizing the values for [A], [B], and Δ[C]/Δt, multiply [A] by [B] to acquire a value of X and consider Δ[C]/Δt as Y. The slope derived from this linear regression will yield k.
Therefore, the results you should have are:
y = 3.60x10⁻² X
Thus, the reaction's rate is:
B) Δ[C]/Δt = 3.60x10⁻² M⁻¹s⁻¹ [A] [B]
I hope this assists you!
