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wlad13
2 days ago
8

Classify these compounds as acid, base, salt, or other.? 1. ch3oh 3. hno3 5. nabr

Chemistry
2 answers:
VMariaS [1K]2 days ago
7 0

Clarification:

Acids are substances that yield hydrogen ions when they dissociate in water (H^{+}).

For instance, HNO_{3} acts as an acid as it liberates H^{+} ions during dissociation.

            HNO_{3} \rightarrow H^{+} + NO^{-}_{3}

On the other hand, bases release hydroxide ions when dissociating in water (OH^{-}).

For example, NaOH behaves as a base because it produces OH^{-} ions.

Salts result from the combination of positively and negatively charged ions.

For example, NaCl qualifies as a salt.

Thus, the classifications for the compounds provided are as follows.

  • CH_{3}OH - Other
  • HNO_{3} - Acid
  • NaBr - Salt

KiRa [971]2 days ago
5 0
<span> </span><span>1. Other (Alcohol)
3. Acidic
5. Salt

</span>
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(a) calculate the %ic of the interatomic bond for the intermetallic compound tial3. (b) on the basis of this result, what type o
Tems11 [846]

Answer :

The percentage ionic character (%IC) equals 10%, indicating the bond is mostly covalent with slight polarity.

Percent Ionic Character:

This reflects the fraction of ionic nature within a polar covalent bond. The formula for %IC (% ionic character) is:

Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^X^a^-^X^b^) * 100

Here, Xa is the electronegativity of atom A and Xb is that of atom B.

Given: The compound is TiAl₃.

Electronegativity of Ti = 2.0

Electronegativity of Al = 1.6 (as shown in the provided image)

Substitute these values into the formula:

Percent Ionic character = 1 - e^-^0^.^2^5 ^*^(^2^.^0^-^1^.^6^) * 100

Percent Ionic character = 1 - e^(^-^0^.^2^5 ^*^0^.^4^) * 100

Percent Ionic character = 1 - e^(^-^0^.^1^) * 100

The value of e⁻¹ equals 0.90.

Therefore, percent ionic character = (1 - 0.90) × 100

Percent Ionic Character = 10%

Because the % IC is only 10%, which is relatively low, the bond is classified as covalent with minimal polarity.

8 0
16 days ago
A gas sample of argon, maintained at constant temperature, occupies a volume of 500. l at 4.00 atm. what is the new volume if th
lorasvet [956]
Boyle's law describes the relationship between gas pressure and volume. 
It asserts that at a constant temperature, pressure is inversely proportional to gas volume.
PV = k
where P represents pressure, V denotes volume, and k is a constant. 
P1V1 = P2V2
where the parameters for the initial condition are on the left, and the parameters for the second condition appear on the right side of the formula.
By substituting values into the equation: 4.00 atm x 500 L = 8.0 atm x V
V calculates to 250 L.
Thus, the new volume becomes 250 L.
6 0
6 days ago
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Which of the following statements describe physical properties and which describe chemical properties? (a) Iron has a tendency t
Anarel [852]

Answer:

Explanation:

a) Iron has the tendency to undergo rusting -- this is a chemical property as it involves a reaction with water and air.

b) Precipitation in industrialized areas often has an acidic nature -- this is also a chemical property due to its interaction with bases or metals.

c) Hemoglobin is red in color -- this is a physical property since it doesn't entail any chemical reactions.

d) When water is left out in sunlight, it evaporates gradually -- this is a physical property because the process can easily be reversed, classifying it as a physical change.

e) During photosynthesis, plants convert carbon dioxide into more complex molecules -- this demonstrates a chemical property since it involves chemical reactions.

8 0
11 days ago
In an experiment a student mixes a 50.0 mL sample of 0.100 M AgNO₃(aq) with a 50.0 mL sample of 0.100 M NaCl(aq) at 20.0°C in a
KiRa [971]

The enthalpy change associated with the precipitation reaction is 84 kJ/mole

Why?

The chemical equation for the reaction can be written as

AgNO₃(aq) + NaCl (aq) → AgCl(s) + NaNO₃(aq)

To determine the enthalpy change, the following equation applies

\Delta H =\frac{Q}{n}

To calculate the heat (Q):

Q=m*C*\Delta T=(100g)*(4.2 J/g*^\circ C)*(21^\circ C-20^\circ C)\\\\Q=420J

Next, we need to calculate the number of moles involved in the reaction (n):

n=[AgNO_3]*v(L)=(0.1M)*(0.05L)=0.005moles

With these two values, we can substitute them into the first equation:

\Delta H= \frac{420J}{0.005moles}=84000J/mole=84kJ/mole

Have a great day!

5 0
5 days ago
1) Assume element X has 2 isotopes: X-125 and X-126. For every 100 atoms of X, 30 of them have a mass of 125.0 u and 70 have a m
lorasvet [956]

Answer:

Explanation:

0.3(125)+0.7(126)=37.5+88.2=125.7

2. The most prevalent isotope is 32, since the average is very close to this value.

6 0
9 days ago
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