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Setler
1 month ago
10

After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an

d an increase of 8% per year, the population is 34,560. Which equation can be used to predict, y, the number of people living in the town after x years? (Round population values to the nearest whole number.)
y = 32,000(1.08)x
y = 32,000(0.08)x
y = 34,560(1.08)x
y = 34,560(0.08)x
Mathematics
2 answers:
Svet_ta [12.7K]1 month ago
4 0

y=32,000(1.08)x

Starting value: 32,000

Growth factor: 1.08, indicating an increase of 8 percent from the initial amount

Inessa [12.5K]1 month ago
4 0

Answer:

y=32000(1+0.08)^x

Step-by-step explanation:

The exponential growth formula is y=a(1+r)^x

Where 'a' signifies the initial population

r is the growth rate and x represents time in years

maintaining a constant population of 32,000. Thus, the initial population is 32,000

with an annual increase of 8%. The growth rate is 8%, equivalent to 0.08

a = 32000 and r = 0.08

Now, substituting all the values into the general formula

y=a(1+r)^x

y=32000(1+0.08)^x

y=32000(1+0.08)^x

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