a student says that if 5x2 = 20, then x must be equal to 2. do you agree or disagree with the student? justify your answer.
2 answers:
We'll verify the student's claim by solving the equation step by step.
Step 1 Divide both sides of the equation by 5:
Step 2 Apply the square root to both sides:
or
The equation has two solutions, and
.
I disagree with the student because is only one root, not the sole solution;
also satisfies the equation.
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Jack swims a total distance of 9*25.0m=225.0 meters in 2 minutes and 34.5 seconds.
The time duration of 2 minutes and 34.5 seconds can be converted to seconds: 2*60sec +34.5 sec= 154.5 s
Jill completes 10*25.0m = 250 m also in 154.5 s.
Therefore,
the speed of Jack calculates to: 225.0 meters / 154.5 s =(225/154.5) m/s = 1.46 m/s
the speed of Jill calculates to: 250.0 meters / 154.5 s =(250/154.5) m/s = 1.62 m/s
Assuming both Jack and Jill start from point 0 moving in the positive direction,
an even number of lengths results in a Displacement of 0, while an odd number results in a Displacement of 25 m
Thus, Jill's average Velocity is 0,
and Jack's average velocity is 25/154.5 = 0.16 m/s
Answer:
Jack's Average Speed: 1.46 m/s
Jill's Average Speed: 1.62 m/s
Jack's Average Velocity: 0
Jill's Average Velocity: 0.16 m/s
The time duration of 2 minutes and 34.5 seconds can be converted to seconds: 2*60sec +34.5 sec= 154.5 s
Jill completes 10*25.0m = 250 m also in 154.5 s.
Therefore,
the speed of Jack calculates to: 225.0 meters / 154.5 s =(225/154.5) m/s = 1.46 m/s
the speed of Jill calculates to: 250.0 meters / 154.5 s =(250/154.5) m/s = 1.62 m/s
Assuming both Jack and Jill start from point 0 moving in the positive direction,
an even number of lengths results in a Displacement of 0, while an odd number results in a Displacement of 25 m
Thus, Jill's average Velocity is 0,
and Jack's average velocity is 25/154.5 = 0.16 m/s
Answer:
Jack's Average Speed: 1.46 m/s
Jill's Average Speed: 1.62 m/s
Jack's Average Velocity: 0
Jill's Average Velocity: 0.16 m/s