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Yanka
10 days ago
15

Which point is a solution of x + 2y ≤ 4?

Mathematics
2 answers:
Inessa [12.1K]10 days ago
7 0

Final answer:

The point (1,1) satisfies x + 2y ≤ 4

Step-by-step reasoning:

To verify if a point is a valid solution for the inequality x + 2y ≤ 4, substitute the value pairs and check the outcome.

So,

(2,4) ⇒ 2 + 2·4 ≤ 4 ⇒ 8 ≤ 4, which is incorrect.

(1,1) ⇒ 1 + 2·1 ≤ 4 ⇒ 3 ≤ 4, this one is correct.

(3,5) ⇒ 3 + 2·5 ≤ 4 ⇒ 13 ≤ 4, this is also incorrect.

(-1,5) ⇒ -1 + 2·5 ≤ 4 ⇒ 9 ≤ 4, this one too is wrong.

Therefore, the only valid point that solves x + 2y ≤ 4 is (1,1)

zzz [11.8K]10 days ago
4 0
The solution is (1,1) since x + 2y <4
=1 + 2(1)
= 3, which is less than 4
You might be interested in
What is a34 of the sequence 9,6,3,
PIT_PIT [11881]

Step-by-step explanation:

What is a34 of the sequence 9,6,3,..

r=a2-a1

r=6-9

r=-3

a34=a1+33.r

a34=9+33.(-3)

a34= 9-99

a34= -90

hope this helps!

bye!

8 0
16 days ago
Read 2 more answers
Simplify the given expression, using only positive exponents. Then complete the statements that follow. [ (x2y3)−1 (x−2y2z)2 ] 2
AnnZ [11894]

Answer: y²z⁴ / x¹²

  • The exponent for x is 12

  • The exponent for y is 2

  • The exponent for z is 4

Explanation:

1) The expression to simplify:

((x^2y^3)^{-1}(x^{-2}y^2z)^2)^2

2) Rule: power of a power:

(x^{-4}y^{-6})(x^{-8}y^8z^4)

3) Rule: product of powers with identical bases

x^{(-2-8)}y^{(-6+8)}z^4

4) Add up the exponents

x^{-12}y^2z^4

5) Transfer the negative exponent to the denominator:

\frac{y^2z^4}{x^{12}}

The exponent attached to x is 12, for y it is 2, and for z it is 4.

4 0
29 days ago
Read 2 more answers
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
Inessa [12133]

Answer: D) \$50\pm\$11.08

Step-by-step explanation:

Based on the provided information, we have

Sample size: n= 15

sample mean: \overline{x}=\$50.50

Sample standard deviation: s= $20

Since the population standard deviation is not known, we utilize a t-test.

For a significance level of 95% confidence: \alpha=1-0.95=0.05

Critical t-value : t_{n-1, \alpha/2}=t_{014,0.025}=2.145  [Using the Student's t-value table]

The required 95% confidence interval yields:-

\overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}\\\\ =\$50.50\pm(2.145)\dfrac{\$20}{\sqrt{15}}\\\\\approx \$50\pm\$11.08

Thus, the sought-after 95% confidence interval for the mean amount spent by credit card customers during their initial visit to the new store in the mall, assuming normal distribution of the spending amounts, is:

\$50\pm\$11.08

5 0
15 days ago
Use Euler's method to obtain a four-decimal approximation of the indicated value. Carry out the recursion of (3) in Section 2.6
AnnZ [11894]

Answer:

At h=0.1, the calculated value of y(1.2) equals 15.920, and for h=0.05, y(1.2) amounts to 16.523.

Step-by-step explanation:

Given,

f(x,y)=\frac{dy}{dx}=2x+3y+1 with y(1)=9.

This means when x=1, y=9 initially.

To determine the value of y= f(x,y) at x_n=x_0+nh=1.2when h=0.1 and h=0.05, we will implement a C program using Euler's method resulting in, for h=0.1:

#include<stdio.h>

float fun(float x, float y)

{

  float f;

  f=2x+3y+1;

  return f;

}

main()

{

   float a,b,x,y,h,t,k;

   printf("\ Enter x0,y0,h,xn:");

   scanf("% f % f % f % f ", & a, &b, &h, &t);

   x=a;

   y=b;

   printf("\n x\t y\n");

   while (x<=t)

{

   k=h*fun(x,y);

   x=x+h;

   y=y+k;

   printf("%0.3f\%0.3f\n",x,y);

}

}

Using initial values x0=1, y0=9, h=0.1, and xn=1.2, we reach results, y(1.2)=15.920.

Subsequently, using values x0=1, y0=9, with h=0.05, and xn=1.2 yields y(1.2)=16.523.

6 0
18 days ago
A child designs a flag in the shape of a rhombus, as shown in the diagram below. Which expression can be used to determine the s
Zina [11976]
<span>Which formula can be applied to find the side length of the rhombus?

 The correct answer is the first choice: 10/Cos(30°)

 Explanation:

 1. The figure shows a right triangle, where the hypotenuse is denoted by "x," and this is the length you are solving for. Therefore, you have:

 Cos(</span>α)=Adjacent side/Hypotenuse
<span>
 </span>α=30°
<span> Adjacent side=(20 in)/2=10 in
 Hypotenuse=x

 2. Inputting these numbers into the equation yields:
</span>
 Cos(α)=Adjacent side/Hypotenuse
<span> Cos(30°)=10/x

 3. Hence, by isolating the hypotenuse "x," you arrive at the expression to find the side length of the rhombus, as shown below:

 x=10/Cos(30°)
</span>

7 0
16 days ago
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