Final answer:
The point (1,1) satisfies x + 2y ≤ 4
Step-by-step reasoning:
To verify if a point is a valid solution for the inequality x + 2y ≤ 4, substitute the value pairs and check the outcome.
So,
(2,4) ⇒ 2 + 2·4 ≤ 4 ⇒ 8 ≤ 4, which is incorrect.
(1,1) ⇒ 1 + 2·1 ≤ 4 ⇒ 3 ≤ 4, this one is correct.
(3,5) ⇒ 3 + 2·5 ≤ 4 ⇒ 13 ≤ 4, this is also incorrect.
(-1,5) ⇒ -1 + 2·5 ≤ 4 ⇒ 9 ≤ 4, this one too is wrong.
Therefore, the only valid point that solves x + 2y ≤ 4 is (1,1)