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10 days ago

Enter the expression N0e−λt, where N0 is N-naught (an N with a subscript zero) and λ is the lowercase Greek letter lambda.

2 answers:

7 0

The problem requests that we express the formula in your inquiry where N0 symbolizes N-naught, and the letter represents the lowercase Greek letter lambda. Therefore, the optimal response or formulation would indicate that lambda denotes the wavelength for this expression. I trust this information meets your expectations.

Inessa [3.9K]10 days ago

5 0

Answer:

Decline in population where the decline rate correlates with the existing population

Step-by-step explanation:

Given that

$N(t)=N_{0} e^{-l t}$

In this context, N(t) indicates the population or the amount of bacteria at time t.

N0 signifies the starting population or N(0)

The presence of a negative exponent for e indicates a decline in population, not growth.

l, the coefficient of t in the exponent of e signifies the decay rate

When the decline is proportional to the presently existing population, we arrive at this equation.

N' = -lN

Separate the variables and integrate to achieve

$N(t)=N_{0} e^{-l t}$

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If m∠1= (7x –19)°, and m∠2 = (x + 5)°, find m∠2.

babunello [3635]

Given :

∠m1 = ( 7x - 19 )°.

∠m2 = ( x + 5 )°.

To Find :

The value of x .

Solution :

As the relationship between angle ∠m1 and ∠m2 isn't specified,

let's presuppose that the sum of ∠m1 and ∠m2 equals 180°.

Thus,

$(7x-19)+(x+5)=180^{\circ}\\\\8x-14=180\\\\8x=194\\\\x=24.25^{o}$

Angle ∠m2 = (24.25 + 5 )° = 29.25°.

Consequently, ∠m2 is 29.25°.

Hence, this solution meets the requirements.

7 0

14 days ago

In 1898 L. J. Bortkiewicz published a book entitled The Law of Small Numbers. He used data collected over 20 years to show that

Svet_ta [4321]

(a) The likelihood of having more than one death in a corps within a single year is 0.1252. (b) The likelihood of experiencing no deaths in a corps throughout 7 years is 0.0130. Detailed Explanation: Define X as the number of soldiers fatally injured by horse kicks in one year. The random variable $X\sim Poisson(\lambda = 0.62)$ . The mathematical function following a Poisson distribution is: $P(X=x)=\frac{e^{-\lambda}\lambda^{x}}{x!};\ x=0,1,2,...$ (a) To calculate the probability of exceeding one death in a corps during a year: P (X > 1) = 1 - P (X ≤ 1) = 1 - P (X = 0) - P (X = 1) $=1-\frac{e^{-0.62}(0.62)^{0}}{0!}-\frac{e^{-0.62}(0.62)^{1}}{1!}\\=1-0.54335-0.33144\\=0.12521\\\approx0.1252$ Thus, the probability of witnessing more than one death within a corps yearly is 0.1252. (b) The average number of deaths in a span of 7 years is: $\lambda=7\times0.62=4.34$ To assess the probability of zero deaths in a corps over 7 years: $P(X=0)=\frac{e^{-4.34}(4.34)^{0}}{0!}=0.01304\approx0.0130$ Therefore, the chance of encountering no fatalities within a corps over 7 years is 0.0130.

6 0

7 days ago

Which are the solutions of x2 = 19x + 1?

AnnZ [3877]

Answer:

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Step-by-step explanation:

We have

$x^2=19x+1$

To recall, the formula for solving a quadratic equation shaped like

$ax^{2} +bx+c=0$

is expressed as

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

For this problem, we have

$-x^{2}-19x-1=0$

Thus,

$a=1\\b=-19\\c=-1$

Substitute into the formula:

$x=\frac{-(-19)\pm\sqrt{-19^{2}-4(1)(-1)}} {2(1)}$

$x=\frac{19\pm\sqrt{365}} {2}$

$x=\frac{19+\sqrt{365}} {2}$

$x=\frac{19-\sqrt{365}} {2}$

$(\frac{19-\sqrt{365}} {2},\frac{19+\sqrt{365}} {2})$

Consequently, the solutions are:

StartFraction 19 minus StartRoot 365 EndRoot Over 2 EndFraction, StartFraction 19 + StartRoot 365 EndRoot Over 2 EndFraction

6 0

7 days ago

Read 2 more answers

If cheese is $4.40 per kilogram, what should i pay for 200 grams

Inessa [3907]

1 kg equals 1,000 grams.

200 grams is a fifth of 1000 grams, which is also a fifth of 1 kg.

Therefore, 200 g equals 1/5 kg or 0.2 kg.

A kilogram of cheese costs <span>$4.40,
</span>
Thus, the price for 0.2 kg of cheese is $\displaystyle{ \frac{0.2kg \cdot \$4.40}{1kg}}=4.40 \cdot0.2 \$= 0.88\$$

Answer: $0.88

8 0

9 days ago

Read 2 more answers

A jet flying at 123 m/s banks to make a horizontal circular turn. The radius of the turn is 3810 m, and the mass of the jet is 2

AnnZ [3877]

Answer:

The required lifting force is 7.95N

Step-by-step explanation:

Force = mv²/r

mass (m) = 2.00105kg, velocity (v) = 123m/s, radius (r) = 3810m

Force = 2.00105 × 123²/3810 = 30273.89/3810 = 7.95N

7 0

1 day ago