A locomotive is accelerating at 1.6 m/s2. it passes through a 20.0-m-wide crossing in a time of 2.4 s. after the locomotive leav

Answer:

b. The loop's current consistently flows in a counterclockwise direction.

Explanation:

As a magnet descends through a wire loop, it generates an induced current within that loop. This induced current arises due to the magnet's movement, leading to a variation in magnetic flux. Lenz's law states that the induced current will act to counteract the change that produces it. In this scenario, the only feasible resistance to the magnet’s fall is through inducing a similar pole on the loop to counteract its downward motion. An induced current that circulates counterclockwise in the wire loop mimics the polarity of a northern pole, thereby repelling the magnet's descent. Furthermore, as the magnet passes the wire loop, this induced north pole will seek to attract the magnet's south end in an effort to halt its downward progression.

a) 600 nm b) 300 nm. To explain, the path difference can be represented as 2t, where t is the film thickness. The wavelength of light in the film is expressed as L' = L/n, with L being the wavelength in air and n representing the refractive index of glass. For part (a), to achieve destructive interference, the equation is 2t = L'/2 = L/2n, leading to L = 4*t*n, which results in 600 nm when calculated. For part (b), for constructive interference, the relation is 2t = L' = L/1.25, giving L = 2tn, which equates to 300 nm.

Answer:

v' = -18 m/s

Explanation:

• Assuming no external forces act during the collision, the overall momentum must be preserved as follows:

       

• The initial momentum can be defined this way (with the initial direction of the ball considered positive):

       

• The final momentum can be formulated as follows (given that v'b moves in the opposite direction to vb):

       

• If we consider that Mc >> mb, we assume the car's speed remains unchanged as a result of the collision, allowing us to substitute V'c for Vc in (3).
• Consequently, we can rewrite (3) like this:

       

• By substituting (2) and (4) back into (1), we arrive at:

       

• By simplifying and rearranging, we can solve for v'b like this:
• , which makes sense because it's as though the ball collided with a wall and simply reversed its velocity post-collision.

Answer:

The cube's mass is calculated to be 420.8 kg.

Explanation:

Given that,

Edge length = 38.9 cm

Density

We need to determine the cube's volume

Using the volume formula

Next, we need to calculate the cube's mass

Employing the density formula

Consequently, the cube's mass is determined to be 420.8 kg.