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Serhud
2 months ago
8

A delivery man starts at the post office, drives 40 km north, then 20 km west, then 60 km northeast, and finally 50 km north to

stop for lunch. use a graphical method to find his net displacement vector.

Physics
1 answer:
Yuliya22 [3.3K]2 months ago
4 0



assuming north-south is along the Y-axis and east-west along the X-axis

X = total X-displacement

from the graph, total displacement in the X-direction is computed as

X = 0 - 20 + 60 Cos45 + 0

X = 42.42 - 20

X = 22.42 m


Y = total Y-displacement

from the graph, total displacement in the Y-direction is computed as

Y = 40 + 0 + 60 Sin45 + 50

Y = 90 + 42.42

Y = 132.42 m

To calculate the magnitude of the net displacement vector, we apply the Pythagorean theorem, yielding

magnitude: Sqrt(X² + Y²) = Sqrt(22.42² + 132.42²) = 134.31 m

Direction: tan⁻¹(Y/X) = tan⁻¹(132.42/22.42) = 80.4 deg north of east


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2 months ago
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Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 4.00. What should be the length of B⃗ so that th
serg [3582]

Answer:

B= \sqrt{65} ≅8.06

Explanation:

Applying the Pythagorean theorem:

C^{2}= A^{2} + B^{2}

Here, C denotes the hypotenuse length, while A and B signify the lengths of the other two sides of the triangle. We can calculate B's length knowing the hypotenuse is 9 and A is 4.

9^{2}=4^{2} + B^{2}

81= 16+ B^{2}

81-16= B^{2}

B= \sqrt{65} ≅8.06

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2 months ago
1. A U.S. manufacturer wants to sell computer equipment to companies in Honduras. Because the U.S. government limits trade with
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A block is suspended from a scale and then lowered into a bucket of water. The density of the water is 1 gm/cm3. The initial rea
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The mass of the block submerged in water measures 1.94 kg. We know the water's density to be 1 gm/cm³, with the initial scale reading at 19 N and a change in this reading amounting to 10 N. To determine the mass of the block when it is immersed in water, we apply the gravitational acceleration g, valued at 9.8.
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When water freezes, it expands about nine percent. What would be the pressure increase inside your automobile engine block if th
Keith_Richards [3271]

Answer:

The increase in pressure within the engine block of the car amounts to 1782.18 ATM.

Explanation:

Provided:

the volume change of water, ΔV = 9%

the bulk modulus for ice, K = 2 x 10⁹ N/m²

It is calculated using the bulk modulus formula;

K = -V\frac{dP}{dV}

so when the water freezes, the pressure increase in the automobile engine block is;

dP = K(\frac{dV}{V} )\\\\dP = K(\frac{0.09V}{V} )\\\\dP = 0.09K\\\\dP = 0.09 (2*10^9)\\\\dP = 1.8 *10^{8} \ N/m^2\\\\dP = 1782.18 \ ATM

Thus, the final pressure increase inside the automobile engine block is 1782.18 ATM.

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