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timurjin
5 days ago
11

Your friend says, “chemical changes are caused by an input in energy. In physical changes, there is no transfer of energy” is yo

ur friend correct? Why or why not?
Physics
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You throw a baseball at an angle of 30.0∘∘ above the horizontal. It reaches the highest point of its trajectory 1.05 ss later. A
kicyunya [3294]

Answer:

The initial speed at which the baseball is thrown is 20.58 m/s

Explanation:

To determine the time taken to reach the peak height in projectile motion, the formula is:

t = (u sin θ)/g

Where u = initial speed of the baseball =?

θ = angle of launch above the horizontal

g = gravitational acceleration = 9.8 m/s²

1.05 = (u sin 30)/9.8

u can be calculated as (1.05 × 9.8)/0.5

u = 20.58 m/s

7 0
2 months ago
A 230mg piece of gold is hammered into a sheet measuring 23cm x 17cm. What is the thickness of the sheet in meters? Density of g
kicyunya [3294]
The sheet's thickness is calculated to be t= 0.0003 mm. The mass provided is m = 230 mg, equivalent to 0.23 g. The area of the sheet is A= 23 x 17 cm², totaling A= 391 cm². Given the density of gold is ρ = 19.32 g/cm³, we assume the sheet's thickness is t cm. From the equation Mass = Density x Volume, we know m = ρ A t. Substituting the values results in: 0.23 = 19.32 × 391 × t, leading to t = 0.000030 cm, or equivalently, 0.0003 mm as the final thickness.
7 0
1 month ago
Medical cyclotrons need efficient sources of protons to inject into their center. In one kind of ion source, hydrogen atoms (i.e
Keith_Richards [3271]

Answer:

The radius is r = 4.434 *10^{-5} \ m

Explanation:

The problem states that

    The magnetic field is  B = 90 mT = 90*10^{-3} \ T

     The electron kinetic energy is  KE = 1.4 eV = 1.4 * (1.60*10^{-19}) =2.24*10^{-19} \ J

In general, for a collision to happen, the centripetal force on the electron in its orbit must equal the magnetic force acting on it  

   This can be mathematically expressed as

   \frac{mv^2}{r} = qvB

=>    r = \frac{m* v}{q * B}

Where  m denotes the electron’s mass, which has a value of m = 9.1 *10^{-31} \ kg  

             v signifies the escape velocity, mathematically represented as

                v = \sqrt{\frac{2 * KE}{m} }

Thus,

       r = \frac{m}{qB} * \sqrt{\frac{2 * KE}{m} }

     applying indices

    r = \frac{\sqrt{2 * KE * m} }{qB}

substituting these values

   

       

r = \frac{\sqrt{2 * 2.24*10^{-19}* 9.1 *10^{-31}} }{ 1.60 *10^{-19}* 90*10^{-3}}

       

r = 4.434 *10^{-5} \ m

     

6 0
2 months ago
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