Two boats start their journey from the same point A and travel along directions AC and AD, as shown below: ABC is a right triang

H' = -2 -5, -3 + 9 = (-7, 6)

1.44 per kilogram

Multiply 1.3 by 2, then deduct 12.7, and after that, divide the result by 7.

(a) The likelihood that all 5 eggs chosen are unspoiled is 0.0531. (b) The probability that 2 or fewer out of the 5 eggs are unspoiled is 0.3959. (c) The probability that more than 1 of the selected 5 eggs are unspoiled is 0.8747. Step-by-step explanation: The complete query is: A subpar carton of 18 eggs has 8 that are spoiled. An unsuspecting chef selects 5 eggs at random for his “Mega-Omelet Surprise.” Calculate the probability of receiving (a) exactly 5 unspoiled eggs, (b) 2 or fewer, and (c) more than 1 unspoiled egg. Define X = number of unspoiled eggs. In the faulty carton, 8 eggs are spoiled. The probability of selecting an unspoiled egg is independent of others. Provided that a chef randomly picks 5 eggs, the variable X follows a Binomial distribution with parameters n = 5 and p = 0.556. Success is defined as selecting an unspoiled egg. The probability mass function of X is as follows: (a) Calculate the probability of selecting all unspoiled eggs. Thus, this probability is found to be 0.0531. (b) For 2 or less unspoiled eggs, the probability is computed: P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2), resulting in a probability of 0.3959. (c) For more than 1 unspoiled egg: P (X > 1) = 1 - P (X ≤ 1), yields a final probability of 0.8747.

To solve simple equations like this, it's essential to apply the order of operations defined by PEMDAS. This acronym represents the sequential operations needed for solving equations.
PEMDAS indicates Parentheses, Exponents, Multiplication, Division, Addition, and Subtraction.
According to PEMDAS, multiplication takes precedence over addition, leading us to:
5 + [1*10] = 5 + 10 = 15.