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frez
5 days ago
12

Two boats start their journey from the same point A and travel along directions AC and AD, as shown below: ABC is a right triang

le with measure of angle ABC equal to 90 degrees and length of AB equal to 300 feet. There is a point C on BD such that measure of angle ACB is 60 degrees and measure of angle ADC is 30 degrees. What is the distance, CD, between the boats?

Mathematics
2 answers:
Inessa [3.9K]5 days ago
4 0

*Refer to the image attached below

Answer:

346.4 ft

Step-by-step Explanation:

The distance between the boats, CD = BD - BC

Using trigonometry, find the length of BD in triangle ∆ABD and also calculate the length of BC in triangle ABC.

Length of BD in triangle ABD:

Opposite side to <30° = 300 ft

Adjacent side = BD

tan(30) = \frac{300}{BD}

BD*tan(30) = 300

Divide both sides by tan(30)

\frac{BD*tan(30)}{tan(30)} = \frac{300}{tan(30)}

BD = 519.6 ft (rounded to nearest tenth)

Length of BC in triangle ABC:

Opposite side to <60° = 300 ft

Adjacent side = BC

tan(60) = \frac{300}{BC}

BC*tan(60) = 300

Divide both sides by tan(60)

\frac{BC*tan(60)}{tan(60)} = \frac{300}{tan(60)}

BC = 173.2 ft (rounded to nearest tenth)

The distance, CD, between the boats is calculated as BD - BC

= 519.6 - 173.2 = 346.4 ft

zzz [4K]5 days ago
3 0
346.4 ft is the accurate solution
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