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ANEK
1 month ago
13

Laura placed a bucket of water in her garden. Over the course of a week, she watched the water evaporate and recorded the volume

of water left in the bucket each day.
Laura found the linear model that best fit the data was V=5.00−0.25n, where n is the number of days since she first placed the bucket and V is the volume of water, in liters, remaining in the bucket.

How many liters of water evaporated from the bucket every day?
How may liters where inside the bucket when Laura first placed it in the garden?
Mathematics
1 answer:
Zina [12.3K]1 month ago
4 0

Response:

1. 0.5 L; 2. 5.00 L  

Detailed explanation:

V = 5.00 - 0.5n

Including units, the equation can be expressed as

V(in litres) = 5.00 L - (0.5 L/day) × (n days)

1. Evaporation rate

When units are included, it becomes clearer that water is evaporating at a rate of 0.5 L per day. In essence, 0.5 L evaporates daily.

The negative sign indicates a reduction in water volume.

2. Initial volume

Initially, when n = 0, we find

V = 5.00 - 0.5×0 = 5.00 - 0 = 5.00 L

This means the bucket originally held 5.00 L of water.

 

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Let x represent the number of caps

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cost for x caps = 6x

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We can set up the following inequality:

Because the total amount cannot exceed 1000, we have

25 + 6x ≤ 1000

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rounding,

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This means she can purchase a maximum of 163 caps.

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1 month ago
(1 point) Suppose F⃗ (x,y)=−yi⃗ +xj⃗ F→(x,y)=−yi→+xj→ and CC is the line segment from point P=(4,0)P=(4,0) to Q=(0,5)Q=(0,5). (a
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I genuinely don’t grasp this response; it seems quite challenging.
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13 days ago
A shipment of 20 similar laptop computers to a retail outlet contains 3 that are defective. If a school makes a random purchase
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Answer:

Step-by-step explanation:

The total count of laptops, N = 20

Defective laptops, n = 3

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Case 1:

Both purchased laptops are non-defective

Probability of selecting 2 non-defective laptops

The count of non-defective laptops equals 20 - 3 = 17

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Probability, P = 17/20 = 0.85

Case 2:

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The probability of choosing 1 defective and 1 non-defective laptop

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25 days ago
According to a survey by Bankrate, of adults in the United States save nothing for retirement (CNBC website). Suppose that adult
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Complete Question

The complete question appears in the first uploaded image

Answer:

a) Yes, selecting 15 corresponds to a binomial experiment

b)

c)

d) P(r = 15) = 3.2768 *10^{-11}

Step-by-step explanation:

Regarding question a:

For an experiment to qualify as binomial

the trials have to be independent

each trial must yield one of two possible outcomes

Given that the selection of 15 individuals is random, we ascertain that the trials are independent and the outcomes are “either the individual saves for retirement or does not save for retirement.”

Therefore, we conclude that the selection of 15 people at random is indeed a binomial experiment.

In question b:

The probability that all selected adults do not save for retirement is mathematically modeled as

P(r = n) = ^nC_r * p^r * q^{n-r}

Here C signifies combination

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n refers to the population size equating to 15

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=>

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The probability that exactly five of the selected adults do not save for retirement is mathematically modeled as

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The probability that at least one of the selected adults opts not to save for retirement can be mathematically expressed as

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P(r \ge 1 ) = 1 - 0.0352

P(r \ge 1 ) = 0.9648

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PIT_PIT [12445]
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