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rjkz
1 month ago
12

Suzanne owns a small business that employs 555 other people. Suzanne makes \$100{,}000$100,000dollar sign, 100, comma, 000 per y

ear, and the other 555 employees make between \$40{,}000$40,000dollar sign, 40, comma, 000 and \$50{,}000$50,000dollar sign, 50, comma, 000 per year.
A dot plot has a horizontal axis labeled, Salary, in thousands of dollars, marked from 40 to 100, in increments of 2. 1 dot is plotted above each of the following values: 40, 42, 44, 46, 48, 100. The dot above 100 is shaded purple.
Suzanne decides to leave the company and keep the other 555 salaries the same.
A dot plot has a horizontal axis labeled, Salary, in thousands of dollars, marked from 40 to 100, in increments of 2. 1 dot is plotted above each of the following values: 40, 42, 44, 46, 48.
How will removing Suzanne's salary from the data set affect the mean and median?
Choose 1 answer:
Choose 1 answer:

(Choice A)
A
The mean will decrease and the median will increase.

(Choice B)
B
The median will decrease and the mean will increase.

(Choice C)
C
Both the mean and median will decrease, but the median will decrease more than the mean.

(Choice D)
D
Both the mean and median will decrease, but the mean will decrease more than the median.
Mathematics
1 answer:
lawyer [12.5K]1 month ago
8 0
The mean will go down
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The sharks are fed three times a day. During the morning feeding , 2/15 tons of fish is fed. During the afternoon feeding, the w
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Answer:

1/6 ton of fish is provided during the night feeding.

Step-by-step explanation:

The fish consumed in the morning is \dfrac{2}{15} tons, and the amount of fish served in the afternoon is \dfrac{1}{15} greater than in the morning. This means

\dfrac{2}{15} +\dfrac{1}{15}

Let’s represent the quantity of fish given at night as x, and if the total fish fed throughout the day equals \dfrac{1}{2}, we have

\dfrac{2}{15}+(\dfrac{2}{15} +\dfrac{1}{15})+x=\dfrac{1}{2}

By summing the numerators on the left side, we derive:

\dfrac{5}{15} +x=\dfrac{1}{2}

and subtracting \dfrac{5}{15} from both sides allows us to isolate x:

x=\dfrac{1}{2} -\dfrac{5}{15}

Since \dfrac{5}{15} =\dfrac{1}{3}, we derive

x=\dfrac{1}{2}-\dfrac{1}{3}

The common denominator for the fractions is 6; hence, we write the equation in the form

x=\dfrac{3}{6}-\dfrac{2}{6}

and simplifying the numerators results in:

\boxed{x=\dfrac{1}{6} }

which indicates the amount of tons fed during the night feeding.

7 0
2 months ago
Steve can​ wash, fold, and iron a basket of laundry in two hours and prepare a meal in one hour. His roommate Mike can​ wash, fo
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Steve possesses an absolute advantage in laundry while Mike holds the comparative advantage in meal preparation.
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1 month ago
Sal recorded the number of crackers in each snack-sized package he opened. Which statement must be true according to the box plo
PIT_PIT [12445]

Response:

The data shows skewness, with the minimum amount of crackers in a pack being 7

Detailed explanation:

Hello,

Firstly, the question lacks completeness due to missing information from the box plot, which I have provided to assist you in answering your inquiry.

Considering the details from the attached image, a symmetric distribution would be centered evenly, but that is not the case here.

The image indicates a positive skew, with the lowest count recorded as 7.

7 0
2 months ago
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Kathleen and Arnob both run from the park entrance along a loop. Kathleen starts walking from the park entrance and gets a 5-mil
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In this scenario, the first step is to assign variables.

We define:

x: time measured in minutes

y: distance covered.

The equations formulated are as follows:

For Kathleen:

y = (\frac{1}{15}) x + 5

For Arnob:

y = (\frac{2}{15}) x

At the moment Arnob meets Kathleen, we have:

(\frac{1}{15}) x + 5 = (\frac{2}{15}) x

Next, we isolate x.

We now have:

(\frac{2}{15}) x - (\frac{1}{15}) x = 5

(\frac{1}{15}) x = 5\\x = (15) * (5)\\x = 75 min

Answer:

Arnob takes a total of 75 minutes to catch up to Kathleen:

d. 75

5 0
3 months ago
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