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jok3333
2 months ago
15

The graph shows the relationship between pounds of grapes, g, and their cost, c.

Mathematics
2 answers:
Inessa [12.5K]2 months ago
5 0
Spending one dollar allows you to buy half a pound of grapes.
To purchase one pound of grapes, you need to pay two dollars.

I hope this clarifies things! If so, please show some appreciation. Have a wonderful day!
AnnZ [12.3K]2 months ago
3 0

Step 1

Define variables:

x – cost in dollars

y – weight of grapes in pounds

A(0,0)\ B(2,1)

We know that the relationship between x and y represents direct variation if it follows the form y/x=k or y=kx.

The line illustrated in the graph represents such a direct variation.

Determine the proportionality constant k.

y/x=k – substitute coordinates of point B –> 1/2=k

The slope corresponds to the constant of proportionality.

Therefore,

m=0.50\ \frac{pounds}{\$}

The linear equation is g=0.50c.

Hence,

Answer to part (a):

You can obtain 0.50 pounds of grapes per dollar spent.

Step 2

Calculate the cost per pound of grapes.

Let

g=1\ pound

Insert the value of g into the equation and solve for c.

g=0.50c

1=0.50c

c=1/0.50=2\$

Therefore,

Answer to part (b):

The price is 2\$ for each pound of grapes.

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lawyer [12517]

Answer: 275 for one, and 325 for two

Step-by-step explanation:

I completed the calculations

3 0
1 month ago
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What is Question I (if m<EBF = 117°, fine m<ABE)​
tester [12383]

Answer:

m∠ABE = 27°

Step-by-step explanation:

* To analyze the figure to address the query

- AC represents a line

- Ray BF crosses line AC at point B

- Ray BF is perpendicular to line AC

Thus, both ∠ABF and ∠CBF are classified as right angles

Which gives us ∠ABF = ∠CBF = 90°

- Rays BE and BD meet line AC at point B

Since m∠ABE is equal to m∠DBE, as indicated by the same symbol in the figure

It implies that BE acts as the angle bisector of angle ABD

Given that m∠EBF = 117°

Then m∠EBF = m∠ABE + m∠ABF

Where m∠ABF = 90°

So, 117° = m∠ABE + 90°

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4 0
2 months ago
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In right triangle qrs, angle r is a right angle. The altitude rt is drawn to hypotenuse qs. If qr is 20 and qs is 25 then find t
lawyer [12517]

Answer:

qt's length = 16

Step-by-step explanation:

The problem states that qrs is a right triangle,

where qr = 20

          sr =?

          qs = 25

          qt =?

1)

Calculate sr

hypotenuse² = base² + height²

sq² = sr² + rq²

25² - 20² = sr²

sr = √(25² - 20²)

sr = 15

2)

When altitude rt is dropped to hypotenuse qs, it creates

two right triangles: rtq and rts.

Δrtq

height = rt

base= tq = 25 - x

hypotenuse = qt = 20

Δrts

height = rt

base= ts = x

hypotenuse = sr = 15

Both triangles share the same height, which is rt

Using the Pythagorean theorem:

      Δ rtq                                           Δ rts

hypotenuse² - base² = height²

20² - (25 - x)² = 15² - x²

400 - (625 + x² - 50x) = 225 - x²

400 - 625 - x² + 50x = 225 - x²

-225 - x² + 50x - 225 + x² = 0

-450 + 50 x = 0

50x = 450

x = 450/50

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Base of Δ rtq = tq = 25 - x

                         tq = 25 - 9

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5 0
2 months ago
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In ΔHIJ, the measure of ∠J=90°, JI = 4, HJ = 3, and IH = 5. What ratio represents the tangent of ∠I?
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Answer:

The ratio  \frac{3}{4} corresponds to the tangent of ∠I.

Step-by-step explanation:

Let’s revisit the trigonometric ratios:

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For triangle HIJ

∵ m∠J = 90°

- The hypotenuse is the side opposite the right angle.

So, HI is the hypotenuse.

∵ HJ = 3 units

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- We’ll apply the Pythagorean Theorem to solve for HJ.

∵ (HJ)² + (IJ)² = (IH)²

∴ 3² + (IJ)² = 5²

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- Subtract 9 from both sides.

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- Utilizing the rule of tan above:

∴ tan(∠I) = \frac{HJ}{IJ}

∴ tan(∠I) = \frac{3}{4}

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Answer:

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dV(t)/dt ∝ V(t)

dV(t)/dt = kV(t)

7 0
2 months ago
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