Answer: 275 for one, and 325 for two
Step-by-step explanation:
I completed the calculations
Answer:
m∠ABE = 27°
Step-by-step explanation:
* To analyze the figure to address the query
- AC represents a line
- Ray BF crosses line AC at point B
- Ray BF is perpendicular to line AC
Thus, both ∠ABF and ∠CBF are classified as right angles
Which gives us ∠ABF = ∠CBF = 90°
- Rays BE and BD meet line AC at point B
Since m∠ABE is equal to m∠DBE, as indicated by the same symbol in the figure
It implies that BE acts as the angle bisector of angle ABD
Given that m∠EBF = 117°
Then m∠EBF = m∠ABE + m∠ABF
Where m∠ABF = 90°
So, 117° = m∠ABE + 90°
- By subtracting 90 from both sides
It follows that m∠ABE = 27°
Answer:
qt's length = 16
Step-by-step explanation:
The problem states that qrs is a right triangle,
where qr = 20
sr =?
qs = 25
qt =?
1)
Calculate sr
hypotenuse² = base² + height²
sq² = sr² + rq²
25² - 20² = sr²
sr = √(25² - 20²)
sr = 15
2)
When altitude rt is dropped to hypotenuse qs, it creates
two right triangles: rtq and rts.
Δrtq
height = rt
base= tq = 25 - x
hypotenuse = qt = 20
Δrts
height = rt
base= ts = x
hypotenuse = sr = 15
Both triangles share the same height, which is rt
Using the Pythagorean theorem:
Δ rtq Δ rts
hypotenuse² - base² = height²
20² - (25 - x)² = 15² - x²
400 - (625 + x² - 50x) = 225 - x²
400 - 625 - x² + 50x = 225 - x²
-225 - x² + 50x - 225 + x² = 0
-450 + 50 x = 0
50x = 450
x = 450/50
x = 9
Base of Δ rtq = tq = 25 - x
tq = 25 - 9
tq = 16
Answer:
The ratio
corresponds to the tangent of ∠I.
Step-by-step explanation:
Let’s revisit the trigonometric ratios:
For triangle HIJ
∵ m∠J = 90°
- The hypotenuse is the side opposite the right angle.
So, HI is the hypotenuse.
∵ HJ = 3 units
∵ IH = 5 units
- We’ll apply the Pythagorean Theorem to solve for HJ.
∵ (HJ)² + (IJ)² = (IH)²
∴ 3² + (IJ)² = 5²
∴ 9 + (IJ)² = 25
- Subtract 9 from both sides.
∴ (IJ)² = 16
- Taking the square root on both sides gives:
∴ IJ = 4 units
To determine the tangent of ∠I, identify the sides that are opposite and adjacent to it.
∵ HJ is opposite to ∠I
∵ IJ is adjacent to ∠I
- Utilizing the rule of tan above:
∴ tan(∠I) = 
∴ tan(∠I) = 
The ratio
indicates the tangent of ∠I.
Answer:
dV(t)/dt = kV(t)
Step-by-step explanation:
The annual change in the car's value, represented by dV(t)/dt, has a proportional relationship with V(t), the car's current value.
dV(t)/dt ∝ V(t)
dV(t)/dt = kV(t)