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Sergio039
3 months ago
15

A spinning disc rotating at 130 rev/min slows and stops 31 s later. how many revolutions did the disc make during this time?

Physics
1 answer:
Ostrovityanka [3.2K]3 months ago
3 0
F = 130 revolutions per minute = 130/60 revolutions per second = 13/6 revolutions per second
t = 31 seconds
wi = 2πf = 2π × 13/6 = 13π/3 radians/second
wf = 0 radians/second = wi + at
a = -wi/t = -13π/3 × 1/31 = -13π/93 radians/second²
wf² - wi² = 2a∅
-169π²/9 radians²/second² = 2 × -13π/93 radians/second² × ∅
∅ = 1209π/18 radians
n = ∅/2π = (1209π/18)/(2π) = 1209/36 ≈ 33.5833 revolutions.
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