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2 months ago

The total energy of a 0.050 kg object travelling at 0.70 c is:

2 answers:

8 0

The answer is 1.1025×10^15 Joules. There is no correct option. The type of energy the object holds is kinetic energy, which is related to the motion of the object. Kinetic energy is calculated using the formula KE = 1/2 MV², where M denotes the mass of the object, which is 0.05 kg in this case, and V signifies its velocity. Given that the object is moving at 0.7 times the speed of light (c), we calculate its speed as 0.7c = 0.7(3×10^8), resulting in a speed of 2.1×10^8. By plugging these values into the kinetic energy equation, we find KE = 1/2 × 0.05 × (2.1×10^8)², yielding KE = 1.1025×10^15 Joules. There is no correct option.

Maru [3.3K]2 months ago

3 0

What does the letter c represent in this context?

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A closed system of mass 10 kg undergoes a process during which there is energy transfer by work from the system of 0.147 kJ per

Softa [3030]

Result: -50.005 kJ

Details:

Provided Data

mass of the system = 10 kg

work done = 0.147 kJ/kg

Elevation change $(\Delta h)=-50 m$

initial speed $(v_1)=15 m/s$

Final Speed $(v_2)=30 m/s$

Specific internal Energy $(\Delta U)=-5 kJ/kg$

according to the first Law of thermodynamics

$Q-W=\Delta H$

$\Delta H=\Delta KE+ \Delta PE +\Delta U$

where KE represents kinetic energy

PE indicates potential energy

U denotes internal Energy

$\Delta H=\frac{m(v_2^2-v_1^2)}{2}+mg(\Delta h)+\Delta U$

$Q=W+\Delta KE+ \Delta PE +\Delta U$

$Q=0.147\times 10+\frac{10\cdot (30^2-15^2)}{2}+10\cdot 9.81\cdot (-5)-5\times 10$

Q = 1.47 + 3.375 - 4.850 - 50

Q = -50.005 kJ

5 0

2 months ago

Ben walks 500 meters from his house to the corner store. He then walks back toward his house, but continues 200 meters past his

Keith_Richards [3271]

Velocity = 71 meters per minute (MPM)
S stands for Speed
D means Distance
T represents Time
To calculate Speed, divide Distance by Time.

6 0

2 months ago

Read 2 more answers

When a vertical beam of light passes through a transparent medium, the rate at which its intensity I decreases is proportional t

Keith_Richards [3271]

Response:

The intensity of light 18 feet underwater is about 0.02%

Clarification:

Employing Lambert's law

Let dI / dt = kI, where k is a proportionality factor, I represents the intensity of incident light, and t indicates the thickness of the medium

Then dI / I = kdt

Taking logarithms,

ln(I) = kt + ln C

I = Ce^kt

At t=0, I=I(0) implies C=I(0)

I = I(0)e^kt

At t=3 & I=0.25I(0), we find 0.25=e^3k

Solving for k gives k = ln(0.25)/3

k = -1.386/3

k = -0.4621

I = I(0)e^(-0.4621t)

I(18) = I(0)e^(-0.4621*18)

I(18) = 0.00024413I(0)

The intensity of light 18 feet underwater is about 0.2%

3 0

2 months ago

How do electromagnetism and gravitation differ from the strong and weak nuclear forces?

ValentinkaMS [3465]

Electromagnetism, which deals with interactions between charged particles, has a considerable range and can create forces that repel like charges while attracting opposites. In contrast, the weak nuclear force is very short-ranged and isn't classified as a force.

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29 days ago

A 50-g cube of ice, initially at 0.0°C, is dropped into 200 g of water in an 80-g aluminum container, both initially at 30°C.

Ostrovityanka [3204]

Answer:

b. 9.5°C

Explanation:

$m_i$ = Ice mass = 50 g

$T_i$ = Initial temperature of water and aluminum = 30°C

$L_f$ = Latent heat of fusion = $3.33\times 10^5\ J/kg^{\circ}C$

$m_w$ = Water mass = 200 g

$c_w$ = Water's specific heat = 4186 J/kg⋅°C

$m_{Al}$ = Aluminum mass = 80 g

$c_{Al}$ = Aluminum's specific heat = 900 J/kg⋅°C

The equation governing heat exchange in the system is presented by

$m_i(L_f+c_wT)+m_wc_w(T-T_i)+m_{Al}c_{Al}=0\\\Rightarrow 0.05\times (3.33\times 10^5+4186\times T)+0.2\times 4186(T-30)+0.08\times 900(T-30)=0\\\Rightarrow 1118.5T-10626=0\\\Rightarrow T=\dfrac{10626}{1118.5}\\\Rightarrow T=9.50022\ ^{\circ}C$

The final equilibrium temperature calculates to 9.50022°C

4 0

2 months ago