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Gekata
3 months ago
13

A group of physics students hypothesize that for an experiment they are performing, the speed of an object sliding down an incli

ned plane will be given by the expression v=2gd(sin(θ)−μkcos(θ))−−−−−−−−−−−−−−−−−−√. For their experiment, d=0.725meter, θ=45.0∘, μk=0.120, and g=9.80meter/second2. Use your calculator to obtain the value that their hypothesis predicts for v.
Physics
2 answers:
serg [3.5K]3 months ago
6 0

Answer:

v = 2.974

Explanation:

Consider rewriting the formula as follows:

v = √(2 * g * d * (sin(θ) - μk * cos(θ))) — this version is clearer.

Substituting values, we get: v = √(2 * 9.80 * 0.725 (0.707 - 0.12 * 0.707)). Calculate 2 * g * d first.

v = √(14.21 * (0.707 - 0.0849)) — compute sin(θ) minus μk times cos(θ).

v = √(14.21 * 0.6222)

v = √8.8422 — find the square root of the result.

v = 2.974

kicyunya [3.2K]3 months ago
6 0

Answer:

v = 2.97 m/s

Explanation:

The velocity equation for the experiment is given as:

v = \sqrt{2gd(sin\theta - \mu_kcos\theta)}

Given the values:

d = 0.725 m

\theta = 45 ^o

\mu_k = 0.120

g = 9.80

This leads to:

v = \sqrt{2(9.80)(0.725)(sin45 - 0.120cos45)}

v = 2.97 m/s

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Answer:

The correct response is:

1. KE Increases, PE Increases, ME Increases.

Explanation:

In this context, kinetic energy refers to the energy associated with an object's motion. Kinetic energy can be defined as the energy required to accelerate a mass from rest to a specified velocity, which it maintains once that speed is reached:

KE = 1/2 mv².

This definition indicates that KE is on the rise.

Potential energy is the energy stored in a body due to its position in a gravitational field:

PE = mgh,

which increases as the object is elevated against gravitational pull.

Since both kinetic and potential energies are increasing, it follows that the total mechanical energy (ME) is also rising:

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3 months ago
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A woman living in a third-story apartment is moving out. Rather than carrying everything down the stairs, she decides to pack he
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Answer:

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Explanation:

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where "g" denotes the local gravitational acceleration.

Since both pendulums are positioned at the same location, the value of "g" will be consistent for both, and when we compare the periods, we find:

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