A crow drops a 0.11kg clam onto a rocky beach from a height of 9.8m. What is the kinetic energy of the clam when it is 5.0m abov
1 answer:
Solution:
The kinetic energy of the clam at an elevation of 5.0 m is 5.19 J and the velocity of the clam at that height is 9.71 m/s.
Explanation:
Throughout its motion, mechanical energy remains constant. We understand that mechanical energy is the summation of potential energy and kinetic energy. Potential energy = , Kinetic energy =
and Mechanical energy =
Initial kinetic energy is zero. At a height of 9.8 m, the mechanical energy of the clam with a mass of 0.11 kg and g=9.81
is calculated as follows: 0.11×9.81×9.8 = 10.58 J.
Mechanical energy of the clam at a height of 5.0 m = =
. Given that mechanical energy is conserved, we can state that the mechanical energy of the clam at a height of 9.8 m is equal to that at 5.0 m. The representation is as follows:
10.58 = 10.58 – 5.39 =
5.19 =
the clam's kinetic energy measures 5.19 J.
Lastly, the speed of the clam at 5.0 m is computed; thus, 5.19 = 94.36 =
= 9.71 m/s. The clam's speed is determined to be 9.71 m/s.
You might be interested in
Answer:
(a) 16.777 miles
(b) Yes, he exceeded the speed limit
Explanation:
(a)
We need to perform the necessary calculations to convert kilometers to miles:
Thus, the distance of the trip in miles is:
(b)
Next, we will compute the man's speed during the journey:
Before that, we must convert minutes to hours:
The resulting speed is:
Consequently:
Thus, it can be concluded that the driver was speeding
a) The student's speed after jumping is 1.07 m/s
b) The final speed of the laser is 10.4 m/s
Explanation:
a)
This issue can be approached through the momentum conservation principle: In the absence of external forces, the combined momentum of the student and the laser must remain unchanged. Hence, we can express:
where:
The initial momentum is zero
m = 42 kg signifies the mass of the laser
v = 1.5 m/s is the laser's final velocity
M = 59 kg is the mass of the student
V denotes the student's final velocity
Solving this for V, we can determine the student's speed:
Thus, the student's final speed calculates to 1.07 m/s.
b)
Here, both the laser and the student have a combined speed of 3.1 m/s prior to the student's jump; thus, the initial momentum isn't zero.
<pSo, we formulate the equation of momentum conservation as:where:
m = 42 kg denotes the mass of the laser
M = 59 kg is the student’s mass
u = 3.1 m/s is their starting velocity
V = -2.1 m/s indicates the student's speed post-jump (she jumps backward)
v signifies the laser's final speed
When we resolve for v, we have:
Learn more about momentum:
Response:D
Clarification:
Provided
mass of object
Distance traveled
resulting velocity
energy conservation occurs starting when the object begins its descent and reaches a speed of 12 m/s
Initial Energy
Final Energy
where is the work done by friction, if any
As friction is present, this indicates an open system with a net external force of zero.
An open system allows for the exchange of energy and mass, and the presence of friction indicates that it is indeed an open system.
Answer:
The water level increases more when the cube is above the raft before it sinks.
Explanation:
The principle involved is based on Archimedes' theory, which states that immersing an object in water will raise the initial water level. This means that the height of the water in the container increases. The increase in water volume corresponds to the volume of the submerged object.
We can consider two scenarios: when the steel cube rests on the raft and when it settles at the pool's bottom.
When the cube rests at the pool’s bottom, the volume will indeed rise, and we can ascertain this using the cube's volume.
Vc = 0.45*0.45*0.45 = 0.0911 [m^3]
When an object floats, it's because the densities of the object and water are in equilibrium.
The formula for density is:
Ro = m/V
where:
m= mass [kg]
V = volume [m^3]
The buoyant force can be calculated with this equation:
Vs > Vc indicates that the combined volume of the raft and the cube exceeds that of the cube alone resting at the bottom of the pool. Hence, when the cube is positioned above the raft, the water level rises more before it becomes submerged.