Answer:
Explanation:
According to the parameters provided,
mass of the clay lump, m₁ = 0.05 kg
initial velocity of the lump, u₁ = 12 m/s
mass of the cart, m₂ = 0.15 kg
initial speed of the cart, u₂ = 0
As the clay adheres to the cart, we have an inelastic collision scenario. Let v represent the combined speed of both the cart and lump post-collision. Given that momentum is conserved, we have:
The resultant speed is v = 3 m/s.
Thus, the final speed of both cart and lump following the collision is 3 m/s. This concludes the solution.
Response:
(a) 
(b) 
Clarification:
Greetings.
(a) In this case, since the starting volume is 18.5 dm³ and the ending volume is 21 dm³ (18.5 +2.5), we can calculate the work at constant pressure as shown below:
This value is negative as it expands against the given pressure.
(b) Furthermore, if the process is conducted reversibly, the pressure might change, hence, we need to calculate the work using:
The moles are calculated based on the provided mass of argon:
Consequently, the work amounts to:
Best regards.
Answer:
407 steps
Explanation:
Based on the question,
P = mgh/t........... Equation 1
Where P stands for power, m is mass, g denotes gravity, h is height, and t represents time.
Rearranging the equation to solve for h, we have:
h = Pt/mg............. Equation 2
Providing values: P = 746 W, t = 1 minute = 60 seconds, m = 70 kg.
Given constant: g = 9.8 m/s²
By substituting into equation 2
h = 746(60)/(70×9.8)
h = 44760/686
h = 65.25 m
h = 6525 cm
Calculating number of steps: 6525/16
The resulting number of steps = 407 steps
Answer:
1.43 x 10¹⁷.
They will move away from each other.
Explanation:
The force acting on each charged sphere is determined as F = mass x acceleration
= 8.55 x 10⁻³ x 25 x 9.8
= 2.095 N
Assuming Q is the charge on each sphere
F = 
Using the values, 2.095 =
We find that Q² = 
Thus, Q = 2.289 X 10⁻⁶
The quantity of electrons = Charge / charge of a single electron
= 
=1.43 x 10¹³.
They will accelerate away from each other.
