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Whitepunk
3 months ago
10

help please!! A runner at a speed of 3.5 m/s comes to a stop in 0.15 seconds. What is the deceleration?

Physics
1 answer:
Maru [3.3K]3 months ago
7 0

Answer:

The runner's deceleration is -23.33 \frac{m}{s^{2} }

Given:

Initial speed = 3.5 \frac{m}{s}

Final speed = 0 \frac{m}{s}

Time taken = 0.15 s

To determine:

Deceleration of the runner =?

Used Formula:

Using the first equation of motion,

v = u + at

Where, v = final speed

u = initial speed

a = deceleration

t = duration

Solution:

<pusing the="" first="" equation="" of="" motion="">

v = u + at

Where, v = final speed

u = initial speed

a = deceleration

t = duration

0 = 3.5 + a (0.15)

-3.5 = 0.15 (a)

a = \frac{-3.5}{0.15}

a = -23.33 \frac{m}{s^{2} }

The negative sign indicates that this represents deceleration.

Hence, the deceleration of the runner is -23.33 \frac{m}{s^{2} }

</pusing>
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Sav [3153]
Arginine is classified as a basic amino acid since it has two amino groups alongside a single acid group. At a low pH level, all ionizable groups are protonated. As the pH rises slightly, the acid group loses its proton. When the pH increases further, one of the amino groups also loses a proton. At considerably high pH levels, none of the ionizable groups remain protonated.

Pkas

<span> <span><span> <span> pka1 = 1.82 </span> <span> pka2 = 8.99 </span> <span> pka3 = 12.48 </span> </span> </span></span> Thus, 9.20 is above the second pKa and below the third pKa. This indicates that the acid has already lost its proton, as has one of the amino groups, while the second amino group remains protonated. When an acid is not protonated, it carries a negative charge. An unprotonated amino group is neutral, whereas when protonated, the amino group bears a positive charge. Therefore, this amino acid exhibits one positive charge (from one of the amino groups) and one negative charge (from the acid), resulting in an overall neutral charge.
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2 months ago
Jack pulls a sled across a level field by exerting a force of 110 n at an angle of 30 with the ground. what are the parallel and
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x = rcos</span>β
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3 months ago
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A power cycle operates between a lake’s surface water at a temperature of 300 K and water at a depth whose temperature is 285 K.
inna [3103]

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b) 0.05

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A)

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Output equals 10 kW

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B)

Maximum Thermal Efficiency of the power cycle is defined as 1 - T1/T2

where T1 = 285 Kelvin

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Question 1
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Answer:

1)  g = 4π² / m, 3) on the x-axis we have the pendulum lengths, while the y-axis shows the squared periods.

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4) Referring to the line equation:

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