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Sergeeva-Olga
3 months ago
15

A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by

Paul has magnitude 43.0 N and direction 61.0∘ south of west.
How much work does Paul's force do during a displacement of the crate that is 12.0 m in the direction 22.0∘ east of north?

Physics
1 answer:
kicyunya [3.2K]3 months ago
6 0

Answer:

W = -510.98 J

Explanation:

Force = 43 N, 61° SW

Displacement = 12 m, 22° NE

The work done is calculated using:

W = F*d*cos(A)

where A is the angle between the applied force and displacement.

The angle A between the force and displacement is determined as A = 61 + 90 + 22 = 172°

Hence, W = 43 * 12 * cos(172)

This results in W = -510.98 J

The negative result indicates that the work is done contrary to the direction of the force applied.

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