A large crate sits on the floor of a warehouse. Paul and Bob apply constant horizontal forces to the crate. The force applied by

Since the roundabout operates at a constant angular velocity, the input power equals the frictional power. Given that the frictional power is 2.5 kW, we can express this as frictional torque multiplied by angular velocity: frictional torque x 0.47 = 2.5 kW. Therefore, solving for frictional torque gives us 2.5 / 0.47 kN.m, which amounts to approximately 5.32 kN.m, leading to a rounded value of 5 kN.m. When the power supply is interrupted, the roundabout experiences deceleration due to the influence of the frictional torque.

The answer is 10pi. I believe this will be helpful.

When Kai removes the burger from the grill and adds cheese, the cheese melts due to the heat retained by the burger from cooking. The warmth remains in the burger for a while, which explains the melting of the cheese.

Result:

,

Explanation:

The electromagnetic attraction between the electron and the proton in the nucleus is equivalent to the centripetal force:

where

k represents the Coulomb constant

e denotes the charge of the electron

e denotes the charge of the proton in the nucleus

r signifies the distance from the electron to the nucleus

v indicates the velocity of the electron

is the mass of the electron

Rearranging for v, we determine

Inside a hydrogen atom, the distance separating the electron from the nucleus is roughly

while the mass of the electron is

and the charge is

By plugging in the values into the formula, we achieve

Answer:

1)

2)

Explanation:

Projectile Motion

When an object is projected near the surface of the Earth at an angle to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.

The height of a projectile can be calculated using

where represents the initial height from ground level, is the vertical component of the initial velocity, and t is the elapsed time.

The vertical speed component is expressed as

1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of .

The peak height is attained when , which allows us to compute the time to reach that height.

Solving for

Thus, the maximum height reached is

We know this value is equal to 8 meters

Continuing with the calculations for

Substituting known values yields

2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate