Sue scored a total of 35 points in two games.she scored 6 times as many points in the second game than in the first.how many mor

n equals 277

9 multiplied by 27 plus 2 multiplied by 31 minus 28 gives n

243 plus 62 minus 28 results in n

305 minus 28 equals n

which means 277 is n

Answer:

The accurate representations are:

- 6x + 15 < 10 - 5x ⇒ 3rd option

A circle is open at 5 with a bold line extending right from 5 ⇒ 4th option (see diagram)

Step-by-step explanation:

Given the inequality is -3(2x - 5) < 5(2 - x)

First, simplify both sides:

∵ -3(2x - 5) = -3(2x) + -3(-5)

Remember that (-)(-) results in (+)

Thus, -3(2x - 5) = - 6x + 15

∵ 5(2 - x) = 5(2) + 5(-x)

Remember that (+)(-) results in (-)

Then, 5(2 - x) = 10 - 5x

Now we have: - 6x + 15 < 10 - 5x

Subtract 15 from both sides

So: - 6x < -5 - 5x

Add 5x to both sides

Thus, - x < - 5

Note that since the coefficient of x is negative, we reverse the inequality sign when dividing both sides by it

∵ The coefficient of x is -1

Therefore, dividing both sides by -1 gives us x > 5

The accurate representations are:

- 6x + 15 < 10 - 5x ⇒ 3rd option

A circle is open at 5 with a bold line extending right from 5 ⇒ 4th option (see diagram)

Answer : y>0

f(x) = 9*2^x

This function is exponential in form

Substituting positive numbers for x yields positive y values

Substituting negative numbers for x also results in positive y values

Therefore, y remains positive regardless of the value of x.

The range comprises all possible y outputs of the function

Since y is always positive, the range is y > 0

Answer:

y = 12x + 16

Step-by-step explanation:

First, simplify both sides of the equation and then isolate the variable.

In Step 1, add 11 to each side.

−1 /2 y+11+−11=6x+3+−11

−1 /2 y=6x−8

In Step 2, divide each side by (-1)/2.

This leads to

y = 12x + 16

Answer:

For a 90º clockwise rotation, the vertex q' (–3, 4) maps to q(4, 3).

According to the 90º counterclockwise rotation rule, q' (–3, 4) transforms to q(–4, –3).

Step-by-step explanation:

Given the rectangle with vertices r'(–4, 4), s'(–4, 1), p'(–3, 1), and q'(–3, 4),

Find the image of vertex q after a 90º rotation.

The rotation rules are:

90º clockwise: (x, y) → (y, –x)

90º counterclockwise: (x, y) → (–y, x)

Applying the clockwise rule to q'(–3, 4) yields q(4, 3).

Applying the counterclockwise rule to q'(–3, 4) yields q(–4, –3).

Thus, clockwise rotation of q' (–3, 4) results in q(4, 3),

and counterclockwise rotation results in q(–4, –3).