Use the formula t = (0.25) s1/2 to find the time t in seconds it will take a stone to drop a distance s of 200 feet. Round your

These plants were utilized to eliminate harmful substances from the environment. In today's world, such crops have evolved into a significant asset and can be a source of profit when managed properly, creating multiple job opportunities along the way. Hope this information is useful.

Density is defined as the mass divided by the volume.

You can alter the density of a substance by adjusting either its mass or volume.

Increasing the volume while maintaining a constant mass will result in a decrease in density (as the denominator of the fraction increases).

Furthermore, reducing the mass while keeping the volume the same will also lower the density (because the numerator is reduced).

Therefore, to achieve a lower density, you should either reduce the mass or increase the volume, keeping the other constant.

I hope this is helpful.

Angular speed is calculated as 2.5 rev/sec.

Answer:

≈ 3077.34

Explanation:

To calculate the flux of F (vector field) across surface S, where

F(x,y,z) = y i − x j + k

and S(u,v) = u cos v i + u sin v j + v k, 0 ≤ u ≤ 2, 0 ≤ v ≤ 5π

We will evaluate the following integral:

Substituting for the surface

x = u cos v

y = u sin v

z = v

Then

F(S(u,v)) = u sin v i - u cos v j + k

The normal vector N is computed as

Where:

N = < cos v, sin v, 0 > X <- u sin v, u cos v, 2v

N = < 2v sin v, -2v cos v, u >

F(S(u,v)).N = < u sin v, -u cos v, >. < 2v sin v, -2v cos v, u >

F(S(u,v)).N = 2uv + u

Thus

≈ 3077.34

Answer:

Explanation:

To begin with, we must determine the pressure acting on the sphere, which is calculated using:

where

denotes the atmospheric pressure

represents the density of the water

signifies the acceleration due to gravity

indicates the depth

By substituting these values,

The sphere's radius is calculated as r = d/2 = 1.1 m/2 = 0.55 m

Thus, the sphere's total surface area can be expressed as

Consequently, the inward force acting on the sphere equals