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Nana76
3 months ago
14

You are waiting to turn left into a small parking lot. a car approaching from the opposite direction has a turn signal on. you s

hould _______________.
Physics
1 answer:
Sav [3.1K]3 months ago
6 0
If the car from the opposite direction activates its turn signal, it is advisable to yield and allow that driver to turn before you initiate your own turn, as they have the right of way. This action can help avert potential complications and demonstrate courtesy on the road.
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A 3030 cmcm wrench is used to loosen a bolt with a force applied 0.30.3 mm from the bolt. It takes 6060 NN to loosen the bolt wh
Softa [3030]

Complete Question

A 30 cm cm wrench is employed to loosen a bolt, with force applied 0.30m from the bolt. It requires 60 N to loosen the bolt when force is applied perpendicular to the wrench. How much force would be necessary if the force were applied at a 30-degree angle from perpendicular?

Response:

The strength needed is F_{\theta } = 69.28 \ N

Clarification:

According to the problem, we know that

    The length of the wrench is L = 30 cm = \frac{30}{100} = 0.3 \ m

    The distance from the bolt is  d = 0.30 m

      The force necessary to loosen the bolt is F = 60 N

       The angle of application is \theta = 30 ^o

Generally, the torque required for loosening the bolt is defined as

       \tau = F * d

        \tau = 60 * 0.3

        \tau = 18 Nm

Now for the bolt to loosen at \theta the torque at 90° must equal that at \theta

Thus, the torque at \theta is represented mathematically as

          \tau = F_{\theta }d cos \theta

substituting values gives us

           18 = F_{\theta } * 0.3 cos (30)

           F_{\theta } = \frac{18}{0.3 cos (30)}

           F_{\theta } = 69.28 \ N

       

7 0
2 months ago
During a snowball fight two balls with masses of 0.4 and 0.6 kg, respectively, are thrown in such a manner that they meet head-o
Yuliya22 [3333]

Answer:

The snowball's speed after the impact is 3 m/s

Explanation:

Given the following:

mass of each ball

m₁ = 0.4 Kg

m₂ = 0.6 Kg

initial speed of both balls = v₁ = 15 m/s

Speed of 1 Kg mass post-collision =?

Applying conservation of momentum

m₁ v₁ - m₂ v₁ = (m₁+m₂) V

A negative velocity indicates that the second ball moves in the opposite direction.

0.4 x 15 - 0.6 x 15 = (1) V

Therefore,

V = - 3 m/s

Consequently,

The snowball's speed following the collision is 3 m/s

8 0
3 months ago
The surface is tilted to an angle of 37 degrees from the horizontal, as shown above in Figure 3. The blocks are each given a pus
inna [3103]

Answer:

Incomplete question: "Each block has a mass of 0.2 kg"

The velocity of the center of mass for the two-block system just prior to their collision is 2.9489 m/s

Explanation:

Provided information:

θ = angle of the surface = 37°

m = mass of each block = 0.2 kg

v = speed = 0.35 m/s

t = collision time = 0.5 s

Question: What is the velocity of the center of mass for the two-block system right before the blocks collide, vf =?

Change in momentum:

delta(P)=F*delta(t)

P_{f} -P_{i}=F*delta(t)

2m(v_{f} -v_{i})=F*delta(t)

v_{i} =0.35-0.35=0

It’s essential to calculate the required force:

F=(m+m)*g*sin\theta

Here, g = acceleration due to gravity = 9.8 m/s²

F=(0.2+0.2)*9.8*sin37=2.3591N

v_{f} =\frac{F*delta(t)}{2m} =\frac{2.3591*0.5}{2*0.2} =2.9489m/s

6 0
3 months ago
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