Argelia has a stack of schoolbooks sitting in the backseat of her car. When Argelia makes a sharp right turn, the books slide to
2 answers:
Answer:
The books are displaced to the left due to inertia and ultimately halt when impacted by the car door.
Explanation:
The movement of the books can be understood through Newton's first two laws:
- The first law (Law of Inertia): an object will remain at rest or continue moving in a straight line unless an unbalanced force acts upon it.
- The second law: if unbalanced forces act on an object, it experiences an acceleration that can be described by the formula
where F is the object's net force, m its mass, and a its acceleration.
Now let's relate this to the scenario:
- When Argelia makes a sharp right turn, the books, which are not secured in the car, maintain their straight-line motion due to inertia so they appear to move left as the car shifts right.
- Upon contacting the car door, the books cease moving due to the second law: the door exerts an unbalanced force, causing the books to decelerate and ultimately come to rest.
You might be interested in
The complete question is;
Block 1 sits on the floor with block 2 resting atop it. Block 3, which is stationary on a frictionless table, is attached to block 2 via a string that passes over a pulley depicted in the illustration below. Both the string and pulley have negligible mass.
Once block 1 is taken away without impacting block 2.
Derive an equation for the acceleration of block 3 considering arbitrary values for m3 and m2. Express your answer in terms of m3, m2, and relevant physical constants as needed.
Answer:
a = (m2)g/(m3 + m2)
Explanation:
Examining the attached illustration, by analyzing the free body diagram for block 3 and utilizing Newton's first law of motion, we reach the following formula;
T = (m3)a - - - (eq 1)
where;
T is the tension in the string
a is acceleration
m3 is the mass of block 3
Simultaneously, doing the same for Block 2, the free body diagram yields the equation; (m2)g - T = (m2)a
Rearranging for T results in;
T = (m2)g - (m2)a - - - (eq 2)
where;
g represents acceleration due to gravity
T is the tension in the string
a is acceleration
m2 is the mass of block 2
To deduce the acceleration, we will substitute (m3)a in place of T in eq 2.
Thus;
(m3)a = (m2)g - (m2)a
(m3)a + (m2)a = (m2)g
a(m3 + m2) = (m2)g
a = (m2)g/(m3 + m2)
