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4 days ago

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"An empty cylindrical barrel is open at one end and rolls without slipping straight down a hill. The barrel has a mass of 19.0 k

g,19.0 kg, a radius of 0.260 m,0.260 m, and a length of 0.650 m.0.650 m. The mass of the end of the barrel equals a fifth of the mass of its side, and the thickness of the barrel is negligible. The acceleration due to gravity is ????

1 answer:

serg [1.1K]4 days ago

5 0

Respuesta:

La aceleración debida a la gravedad, g, del cilindro es 9.81 m/s2

Explicación:

La aceleración que experimenta el cilindro al rodar cuesta abajo desde una colina es siempre constante para cualquier objeto descendiendo en la atmósfera, siendo g=9.8 m/s2 o aproximadamente 10 m/s2.

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Answer:

Explanation:

Within a duration of 60 seconds, six waves are observed.

With a total of 6 waves,

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2 days ago

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Answer:

1)

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2)

$y=7.39\ m$

Explanation:

Projectile Motion

When an object is projected near the surface of the Earth at an angle $\theta$ to the horizontal, it follows a trajectory known as a parabola. The only force acting on it (ignoring wind resistance) is gravity, affecting the vertical axis.

The height of a projectile can be calculated using

$\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}$

where $y_o$ represents the initial height from ground level, $v_{oy}$ is the vertical component of the initial velocity, and t is the elapsed time.

The vertical speed component is expressed as

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1) To proceed, we will determine the initial vertical velocity component since we lack sufficient data to calculate the absolute value of $v_o$ .

The peak height is attained when $v_y=0$ , which allows us to compute the time to reach that height.

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$\displaystyle t_m=\frac{v_{oy}}{g}$

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$\displaystyle y_o+\frac{v_{oy}^2}{2g}=8$

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$\displaystyle v_{oy}=\sqrt{2g(8-y_o)}$

Substituting known values yields

$\displaystyle v_{oy}=\sqrt{2(9.8)(8-1.5)}$

$\displaystyle v_{oy}=11.29\ m/s$

2) At t=1.505 seconds, the ball is positioned above Julie’s head; we can calculate

$\displaystyle y=y_o+V_{oy}t-\frac{gt^2}{2}$

$\displaystyle y=1.5+(11.29)(1.505)-\frac{9.8(1.505)^2}{2}$

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Explanation:

Here’s a revised version of the requirements;

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15 days ago

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kicyunya [1025]

Answer:

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Explanation:

Here is the data provided:

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solution:

We calculate the root mean square velocity of air particles. This can be expressed as:

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10 days ago