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Ivanshal
3 months ago
15

What is the average acceleration of a car that is initially at rest at a stoplight and then accelerates to 24 m/s in 9.4 s?

Physics
2 answers:
kicyunya [3.2K]3 months ago
8 0

serg [3.5K]3 months ago
5 0
B) a= 2.6 m/s² Explanation: In the case of the car's uniform acceleration, the following formula is used: vf= v₀+a*t (Formula 1) where: t is time in seconds (s), v₀ denotes initial speed in m/s, vf represents final speed in m/s, and a signifies acceleration in m/s². Given that v₀=0, vf = 24 m/s, and t= 9.4 s, we substitute these values into formula (1): 24 m/s = 0 + a*9.4s, leading to a = (24 m/s) / (9.4s), which calculates to a= 2.6 m/s².
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Keith_Richards [3271]

Answer: small barrel gun

Explanation:

It is noted that short barrel guns have a higher muzzle velocity for bullets compared to longer barrel guns.

Acceleration is determined by the change in velocity with respect to time.

a=\dfrac{\Delta v}{\Delta t}

For short barrel guns, the bullet reaches its muzzle velocity more quickly, leading to greater acceleration than that of bullets from long barrel guns.

7 0
4 months ago
A brass lid screws tightly onto a glass jar at 20 degrees C. To help open the jar, it can be placed into a bath of hot water. Af
serg [3582]

Answer:

0.0016 cm

Explanation:

\alpha_b = The thermal expansion coefficient for brass = 19\times 10^{-6}\ /^{\circ}C

\alpha_g = The thermal expansion coefficient for glass = 9\times 10^{-6}\ /^{\circ}C

\Delta T = Temperature change = (60-20)^{\circ}C

R_0 = Original radius = 4 cm

The change in radius is described by

R=R_0(1+\alpha\Delta T)

The radius difference between the lid and the jar

\Delta R=R_b-R_g\\\Rightarrow \Delta R=R_0(1+\alpha_b\Delta T)-R_0(1+\alpha_g\Delta T)\\\Rightarrow \Delta R=R_0(\alpha_b-\alpha_g)\Delta T\\\Rightarrow \Delta R=4\times (19\times 10^{-6}-9\times 10^{-6})\times (60-20)\\\Rightarrow \Delta R=0.0016\ cm

The gap measures 0.0016 cm or 0.000016 m

8 0
3 months ago
When a mass m1is placed on top of a spring and allowed to come to rest, the spring iscompressed by an amount x1. How much would
Keith_Richards [3271]
x₂ = 16 g m₂ / k. The spring's behavior adheres to Hooke's law, expressed as F = k x. For equilibrium illustrated in Newton's diagram, F - W = 0 and k x₁ = m₁ g, leading to k = g m₁ / x₁. In an elevator moving upward with acceleration, the relation adjusts to F - W = m a, which gives F = m (g + a). Compression becomes K x₂ = 4 m (g + 3g), simplifying to x₂ = 4m / k (4g) and ultimately x₂ = 16m2 / k g.
4 0
2 months ago
The resistivity of iron is 1 x 10 -7 Ωm. The resistance of a iron wire of particular length and thickness is 1 ohm. If the lengt
Maru [3345]
2×10⁻⁷ Ωm. From the problem, we have R = 4ρL/πd². Hence, solving for ρ, we get ρ = Rπd²/4L. When both the length and diameter are doubled while keeping the resistance fixed, the new resistivity is derived as ρ' = 2(1×10⁻⁷), resulting in ρ' = 2×10⁻⁷ Ωm.
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3 months ago
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