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n200080
1 month ago
6

Which graph shows the solution to the system of linear inequalities? y ≥ 2x + 1 y ≤ 2x – 2

Mathematics
1 answer:
tester [12.3K]1 month ago
3 0

Answer:

Step-by-step explanation:

Consider the two inequalities:

y \ge 2x + 1\\ y \le 2x - 2

To plot them, let's first write their corresponding equations:

y = 2x + 1 \\y = 2x - 2

Next, we need to identify at least two points for each equation to create the graph.

For Equation y = 2x + 1:

By setting x = 0, we find y = 1

If we set y = 0, then x = -\frac{1}2.

The two points identified are (0, 1) and (-\frac{1}2, 0).

For Equation y = 2x -2:

By putting x = 0, we arrive at y = -2

Setting y = 0 leads us to find x = 1.

The two points we got here are (0, -2) and (1, 0).

Now we can proceed to plot these points.

Let's try point (1, 4) to check if it satisfies the first inequality.

4 \ge 2 \times 1 +1\\\Rightarrow 4 \ge 3

Which is verified as true.

Thus, the shaded area would extend towards point (1,4).

Now, let's see if point (1, 4) holds for the second inequality.

4 \le 2 \times 1 -2\\\Rightarrow 4 \le 0\ [\bold{False}]

This indicates that the shaded area would be opposite to point (1,4).

<pplease refer="" to="" the="" attached="" graph="" for="" further="" clarity.="">

There is no solution available for this system since a common shaded area does not exist..

</pplease>
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For three consecutive years, Sam invested some money at the start of the year. The first year, he invested x dollars. The second
AnnZ [12381]

Let’s define x as the amount invested by Sam in the first year.
Here are the corresponding expressions derived from the provided descriptions for Sam's investments.

For Sam:
2nd year: investment = 5x/2 - 2000
3rd year: investment = x/5 + 1000

The total Sam invested is:
x + (5x/2 - 2000) + (x/5 + 1000)

Next, we can form the expressions for Sally’s investments.
For Sally
1st year: investment = 3x/2 - 1000
2nd year: investment = 2x - 1500
3rd year: investment = x/4 + 1400

Thus, Sally's total investment is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

Setting both totals equal gives us:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)

Solving for x,
x = 2000
For Sally's investment for the third year:
investment = x/4 + 1400 = (2000/4 + 1400) = 1900

RESULTS:
Sam's first year = $2000
Sally's third year = $1900
3 0
12 days ago
Joaquin is four more than half Marjorie’s age. Marjorie is also 32 less than three times Joaquin’s age.
babunello [11817]

Answer:

Her age is 40 years

Step-by-step explanation:

Let Jerry's age be represented as j

Let Marjorie's age be denoted as m

The first part of the question states:

j = 4 + m/2

For the second equation:

m = 3j - 32

Multiply the first equation by 2 to get:

2j = 8 + m

Leading to m = 2j - 8

Set both equations for m equal to each other:

2j - 8 = 3j - 32

By simplifying, we get:

3j - 2j = 32 - 8

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Now substituting back:

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m = 2(24) - 8

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Answer:

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Please refer to the attached document for a comprehensive resolution and step-by-step explanation

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17 days ago
What is the equation of the line graphed below?
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1/2x + y = 3

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19 days ago
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What values of b satisfy 4(3b + 2)2 = 64?
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Starting with the equation 4(3b + 2)² = 64, if we divide both sides by 4 we obtain (3b + 2)² = 16. By taking the square root of both sides, we derive two cases: (3b + 2) = 4 and (3b + 2) = -4. Solving each equation for b yields: 3b = 2 or 3b = -6, leading to b values of 2/3 and -2. Ultimately, the results specify that b = 2/3 and b = -2.
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