Answer:
box 1: monomial
box 2: binomial
Step-by-step explanation:
rationale: The volume of Box 1 is represented by a monomial multiplied by another monomial, resulting in a monomial.
Conversely, the volume of Box 2 is represented by a monomial multiplied by a binomial, producing a binomial.
We are given the triangle
△ABC, with m∠A=60° and m∠C=45°, and AB=8.
To start, we will calculate all angles and sides.
Finding angle B:
The total of all angles in a triangle equals 180.
m∠A + m∠B + m∠C = 180.
Substituting the known values,
60° + m∠B + 45° = 180.
This gives us m∠B = 75°.
Calculating BC:
Using the law of sines,

We can substitute in the values.



Finding AC:

Now we'll input the values.



Calculating Perimeter:

We substitute values here as well.


Calculating Area:
Using the area formula,

we can then insert values.

...............Answer
Answer:
(C) They have the same coefficient of variation
Step-by-step explanation:
The coefficient of variation (CV) is calculated using the formula:

Where
represents standard deviation and
represents the mean.
Bob's average weight is 200 pounds with a standard deviation of 16 pounds
This indicates that
.
Thus, his coefficient of variation is

Mary's average weight is 125 pounds, with a standard deviation of 10 pounds.
This implies 
Therefore, her coefficient of variation is

Since both have the same coefficient of variation, the accurate response is.
(C) They have the same coefficient of variation
Answer:
Hours
Step-by-step explanation:
This is an incorrect figure.
The behavior of the spring can be described using either a sine or cosine function. The spring's maximum displacement is 6 inches, occurring at t=0, which we will define as the positive peak. Therefore, we can express the function as:
6sin(at+B). The spring's period is 4 minutes, which means the time factor in the equation must complete a cycle (2π) in 4 minutes. This gives us the equation 4min*a=2π, leading to a=π/2. Generally, a=2π/T where a is the coefficient and T is the period. For B, since sin(π/2)=1, we determine B=π/2 because at t=0, the equation becomes 6sin(B)=6. Therefore, we substitute to form f(t)=6sin(πt/2+π/2)=6cos(πt/2)
due to trigonometric relations.