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3 months ago

The independent variable of interest in an ANOVA procedure is called a a. partition. b. factor. c. treatment. d. response.

Mathematics

1 answer:

AnnZ [12.3K]3 months ago

4 0

Answer:

Option b (factor) is the right answer.

Step-by-step explanation:

ANOVA can be utilized to explore if any other statistically significant differences are seen among the results of two or more completely separate categories.

There are two main types of independent variables:

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If the explanatory variables are particularly potent, we then adjust the variable's parameter to evaluate its influence on something like a specific factor.

Some options are not suitable for the context provided. Therefore, choice B was the most appropriate for this situation.

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Harry put blue and green marbles in a bag. Exactly 3/4 of the marbles in the bag are blue. Which of the following could be the t

tester [12383]

Answer:

Step-by-step explanation:

When you multiply 3/4 by A, B, or C, it results in a decimal value; however, multiplying 3/4 by 8 yields 6, which is a whole number.

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3 months ago

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Given: ΔABC, AC = BC, AB = 3 CD⊥ AB, CD = 3 Find: AC

Leona [12618]

Answer:

3 $\sqrt{5}$ /2

Step-by-step explanation:

Given that AC = BC, this is an isosceles triangle.

Since CD is perpendicular to AB, we find AD = DB = 0.5AB = 3/2

Now considering triangle ACD,[TAG_17]]

we will use Pythagoras' theorem,

AC = $\sqrt{AD^{2} + CD^{2} }$

AC = 3 $\sqrt{5}$ /2

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2 months ago

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11. Given the kite shown below with TW=5 cm, TX = 12 cm and TZ = 4 cm.

Zina [12379]

Answer: 39 cm

Step-by-step explanation:

Let's consider the kite as depicted in the image provided, where TW=5 cm, TX=12 cm, and TZ=4 cm.

First, we need to determine the lengths of the unknown sides to calculate the perimeter, assuming that both the top and bottom parts consist of isosceles triangles.

For the upper segment, we will apply the Pythagorean Theorem to triangle TWZ, with TZ measuring 4 cm and TW being 5 cm. Hence, we must calculate WZ:

$TW^{2}=TZ^{2}+WZ^{2}$

By isolating $WZ$ :

$WZ=\sqrt{TW^{2}-TZ^{2}}=\sqrt{(5 cm)^{2}-(4 cm)^{2}}$

$WZ=3 cm$

For the lower segment, we can apply the Pythagorean Theorem to triangle WZX, where WZ=3 cm and ZX=8 cm. We need to find WX:

$WX^{2}=WZ^{2}+ZX^{2}$

$WX=\sqrt{WZ^{2}+ZX^{2}}=\sqrt{(3 cm)^{2}+(8 cm)^{2}}$

$WX=8.54 cm$

Now that the lengths of all sides are identified, the perimeter can be calculated:

$5cm + 5cm +8.54 cm + 8.54 cm=27.08 cm$

The closest option to this calculated value is 39 cm.

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3 months ago

Apolline is mowing lawns for a summer job. For every mowing job, she charges an initial fee plus a constant fee for each hour of

Svet_ta [12734]

Answer:

Base Charge = $7

Additional Fees = $7

Step-by-step explanation:

Let x represent the base charge and y for the additional fees.

For a job that lasts 5 hours, we obtain:

$42 = x + 5y$

For the 3-hour task

$28 = x + 3y$

Finding x and y;

$42 = x + 5y$

$28 = x + 3y$

Deduct the second equation from the first

$42 - 28 = x - x + 5y - 3y$

$14 = 2y$

Calculate y

$y = 14/2$

$y = 7$

Replace 7 with y in the first equation

$42 = x + 5y$

$42 = x + 5 * 7$

$42 = x + 35$

$x = 42 - 35$

$x = 7$

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3 months ago

Elia rode her bicycle from her house to the beach at a constant speed of 18 kilometers per hour, and then rode from the beach to

Svet_ta [12734]

Answer:

Elia took $\dfrac{5}{11}$ hour to cycle from her residence to the beach, $\dfrac{6}{11}$ hour to return, and traveled

$8\dfrac{2}{11}$ kilometers from her home to the beach and

$8\dfrac{2}{11}$ kilometers on her way back.

Step-by-step explanation:

1. Let b represent the hours Elia spent cycling to the beach, and p the time taken for the return trip to the park. The combined time for both rides equals 1 hour, represented as

b + p = 1

2. With a constant speed of 18 km/h on her way to the beach, in b hours, she covered 18b kilometers. She then rode back from the beach to the park at a steady speed of 15 km/h, which amounted to 15p kilometers.

Since the distances for both trips are identical, we establish

18b = 15p

3. Solve the two equations:

$\left\{\begin{array}{l}b+p=1\\ \\18b=15p\end{array}\right.$

Using the first equation

$b=1-p$

Insert this solution into the second equation

$18(1-p)=15p\\ \\18-18p=15p\\ \\18=18p+15p\\ \\33p=18\\ \\p=\dfrac{18}{33}=\dfrac{6}{11}\\ \\b=1-\dfrac{6}{11}=\dfrac{5}{11}$

Elia took $\dfrac{5}{11}$ hour to cycle to the beach, $\dfrac{6}{11}$ hour on her return, and covered

$18\cdot \dfrac{5}{11}=\dfrac{90}{11}=8\dfrac{2}{11}$ kilometers going to the beach and

$15\cdot \dfrac{6}{11}=\dfrac{90}{11}=8\dfrac{2}{11}$ kilometers returning to her home.

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3 months ago

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