Sanjit drives the 45 km distance between York and Leeds he then drives a further 42 km from Leeds to Blackpool
2 answers:
The average speed for his entire journey from York to Blackpool is about 61.41 km/h.
Here’s a breakdown of how we arrive at this:
The distance he travelled from York to Leeds is 45 km,
and the speed during that section was 54 km/h.
Therefore, the time taken to travel from York to Leeds is 45/54 hours (since Time = Distance/Speed).
Next, the distance from Leeds to Blackpool is 42 km,
and the time for that leg of the journey is 35 minutes, which is 35/60 hours.
This leads to the total duration for his trip as
hours.
The cumulative distance covered equals 45 + 42 = 87 km.
Thus, his average speed is calculated as:
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Answer: x ≥ 3.2 OR x ≤ -0.75
Here's how to solve the compound inequality step-by-step: start by separating it into two inequalities. For the first one, 5x - 4 ≥ 12, add 4 to both sides to remove the constant, leaving 5x ≥ 16. Then divide both sides by 5 to isolate x, resulting in x ≥ 3.2.
Now for the second part, 12x + 5 ≤ -4, subtract 5 from both sides to obtain 12x ≤ -9. Dividing both sides by 12 gives x ≤ -9/12, which simplifies to x ≤ -0.75. So, combining both, the solution is x ≥ 3.2 OR x ≤ -0.75.
Here, 'a' relates to 0.
There are two scenarios for 'r' and 't'.
Scenario 1.
Both are positioned on the same side to the right of 'a'.
In this case, 'r' would equal 5, and 't' would equal 7.
The midpoint between 'r' and 't' is .
Scenario 2.
If both are found to the left of 'a'.
Then 'r' would equal -5, while 't' would equal -7.
The midpoint is .
Scenario 3.
If 'r' is right of 'a' and 't' is left of 'a'.
Thus 'r' equals 5 and 't' equals -7.
The midpoint is .
Scenario 4.
If 'r' is left of 'a' while 't' is right of 'a'.
In this case, 'r' corresponds to -5 and 't' corresponds to 7.
The midpoint is .
The potential midpoint coordinates for 'rt' are 6, -6, 1, and -1.