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Paha777
3 months ago
12

Sanjit drives the 45 km distance between York and Leeds he then drives a further 42 km from Leeds to Blackpool

Mathematics
2 answers:
PIT_PIT [12.4K]3 months ago
8 0

For 45 km at 54 km/h,

<span>we have 45 / 54 = 5/6.</span>

<span>Therefore, he takes 5/6 of an hour, which is 50 minutes.</span>

<span>The resulting average speed is 61.4117 km/h.</span>

Leona [12.6K]3 months ago
3 0

The average speed for his entire journey from York to Blackpool is about 61.41 km/h.

Here’s a breakdown of how we arrive at this:

\text{ The average speed}=\frac{\text{Total distance covered}}{\text{Total time taken}}

The distance he travelled from York to Leeds is 45 km,

and the speed during that section was 54 km/h.

Therefore, the time taken to travel from York to Leeds is 45/54 hours (since Time = Distance/Speed).

Next, the distance from Leeds to Blackpool is 42 km,

and the time for that leg of the journey is 35 minutes, which is 35/60 hours.

This leads to the total duration for his trip as

=\frac{45}{54}+\frac{35}{60}=\frac{450+315}{540}=\frac{765}{540}=\frac{17}{12} hours.

The cumulative distance covered equals 45 + 42 = 87 km.

Thus, his average speed is calculated as:

=\frac{87}{17/12}= \frac{12\times 87}{17}=\frac{1044}{17}=61.4117647\approx 61.41\text{ km per hour}

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