Twelve of the 20 students in Mr. Skinner’s class brought lunch from home. Fourteen of the 21 students in Ms. Cho’s class brought

Answer:

The height of the rock after 3.2 seconds has passed.

Step-by-step explanation:

To respond to this question, we must examine the provided function:

h(t) = –16t2 + 28t + 500

This function h(t) denotes the height of a rock t seconds after it has been launched by a slingshot.

t signifies time (in seconds)

As t is the independent variable and h is the dependent variable, the height of the rock at 3.2 seconds is expressed as h(3.2).

If you have any further questions or need clarification, feel free to ask.

Answer:

The 10th term in the geometric progression is 29.

Step-by-step explanation:

Given: In a geometric series, [T3 = 18] and [T6 = 486].

To find: The term [T10]?

Solution:

A geometric sequence takes the form [a, ar, ar^2,...]

Where, a represents the first term, and r denotes the common ratio.

The nth term is expressed as [Tn = a * r^(n-1)]

From the information provided: [T3 = a * r^2 = 18]

And [T6 = a * r^5 = 486]

By dividing the second equation by the first:

[(a * r^5) / (a * r^2)] = 486 / 18

[r^3 = 27]

Taking the cube root provides: r = 3.

Inserting r into one of the equations allows us to solve for a.

Substituting r gives: [T3 = a * r^2 = 18]

Thus, the first term is a = 2, and the common ratio is r = 3.

The 10th term in the geometric progression is computed as:

[T10 = a * r^(10-1)]

[Thus, T10 = 29.]