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frozen
1 month ago
4

Mel slides down waterslide A, and Victor slides down waterslide B. After 2 seconds, Mel was 50 feet in the air, and after 5 seco

nds, she was 35 feet in the air. After 1 second, Victor was 60 feet in the air, and after 4 seconds, he was 50 feet in the air. Who was descending at a faster rate?
Mel: (2, 50) and (5, 35)

Victor: (1, 60) and (4, 50)

Mel’s rate of change is____.That means that her height in the air decreases _____ feet every second.

Victor’s rate of change is _____ . That means that his height in the air decreases _____ feet every second.
Mathematics
2 answers:
Leona [12.6K]1 month ago
7 0
Begin by calculating the slopes for both individuals using the formula:
m = (y2 - y1) / (x2 - x1)
Mel: points (2, 50) and (5, 35)
m1 = (35 - 50) / (5 - 2) = -15 / 3 = -5 feet per second
Victor: points (1, 60) and (4, 50)
m2 = (50 - 60) / (4 - 1) = -10 / 3 ≈ -3.333 feet per second

Conclusion:
Mel descends faster.
Mel's negative slope indicates she drops 5 feet every second.
Victor's negative slope means his height decreases by about 3.33 feet every second.
Leona [12.6K]1 month ago
6 0

Answer:

Coordinates: 50, 35

Step-by-step explanation:

Points to consider: 60 and 4.50

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Katherine has 32 pop songs and 72 rock songs on her mp3 player that she will be organizing into playlists. She wants to put an e
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Katherine will create at least 8 playlists. Each of these will feature 4 pop songs and 9 rock songs.

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The box plots compare the exam scores of Ms. Dobson’s class to the rest of the students who took the test in the district.
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Answers:

A. Ms. Dobson’s class exhibits a narrower score range;

B. The district demonstrates a higher interquartile range; and

C. The score of fifteen is an outlier for the district.

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The score range in Ms. Dobson's class spans from a low of 40 to a high of 95, which results in a range of 95-40 = 55.  In contrast, the district's scores range from 15 to 100, yielding a range of 100-15 = 85.  Thus, Ms. Dobson's class possesses a smaller score range.

The interquartile range (IQR) is attained by subtracting Q1, the first quartile, from Q3, the third quartile.

For Ms. Dobson's class, Q1 equals 70 and Q3 equals 80, leading to an IQR of 80-70 = 10.  In the district, Q1 is 55 and Q3 is 75, resulting in an IQR of 75-55 = 20.  Thus, the district has a more extensive interquartile range.

An outlier is defined as any score that falls below 1.5 times the interquartile range from Q1 or above 1.5 times the interquartile range from Q3.

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