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Radda
1 month ago
14

What is the true solution to In 20+In 5= 2 In x?#31​

Mathematics
1 answer:
Inessa [12.5K]1 month ago
5 0

Answer:

ln20+ln5=2lnx

ln(20x5)=lnx^2

ln100=lnx^2

100=x^2

taking square roots

x=10

Hope this assists!

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Find the slope of a pipe that slopes down 2/5 inch per foot.
babunello [11817]

Answer:

m=\frac{1}{30}

Step-by-step explanation:

To determine the slope, divide the rise by the run to calculate the slope.

Note that

1 ft = 12 in

Let

y ----> the rise

x ----> the run

m ----> the slope

m=\frac{y}{x}

the values are given as

y=2/5\ in

x=1\ ft=12\ in

m=\frac{y}{x}

substituting these values gives

m=\frac{(2/5)}{12}

m=\frac{2}{60}

Simplifying further

m=\frac{1}{30}

3 0
3 months ago
Read 2 more answers
AA3+2=AAA<br>CC6+6=CBB<br> ABC= ?
Zina [12379]
From AA3+2=AAA, it follows that 3+2 equals A, so A must be 5.
Given CC6+6=CBB, since 6+6 equals 12, the final digit has to be 2, making B=2. Additionally, adding 6 to 6 increases the tens digit by one, meaning B is one more than C, so C=1 (since 2-1=1). Therefore, ABC equals 521.
9 0
3 months ago
Albert Abbasi, VP of Operations at Ingleside International Bank, is evaluating the service level provided to walk-in customers.
babunello [11817]

Answer:

The likelihood that Albert's sample of 64 will have a mean waiting time between 13.5 and 16.5 minutes is 0.9973.

Step-by-step explanation:

Prior concepts

A normal distribution is characterized as a "probability distribution that is symmetric around the mean, indicating that data close to the mean are more frequent than those further away".

The Z-score refers to "a statistical measurement that reflects the relationship of a value to the mean of a group, measured in standard deviations".

Let X denote the random variable of interest, and we identify its distribution:

X \sim N(\mu=15,\sigma=4)

Also, let \bar X signify the sample mean, whose distribution is:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

In this case, \bar X \sim N(15,\frac{4}{\sqrt{64}})

Solution to the problem

We seek this probability

P(13.5

Applying the Z-score formula to the probability results in:

P(13.5

=P(\frac{13.5-15}{\frac{4}{\sqrt{64}}}

To determine these probabilities, we can refer to normal distribution tables, use Excel, or a calculator.

P(-3

The likelihood that Albert's sample of 64 will have a mean waiting time between 13.5 and 16.5 minutes is 0.9973.

7 0
1 month ago
Thirty-six of the staff of 80 teachers at a local intermediate school are certified in Cardio-Pulmonary Resuscitation (CPR). In
Zina [12379]

Answer:

In approximately 81 days, it is likely that the teacher on bus duty will be certified in CPR

Step-by-step explanation:

The probability of a teacher obtaining certification in Cardio-Pulmonary Resuscitation (CPR) is as follows:

36 out of 80

Hence

p = \frac{36}{80} = 0.45

In a school year lasting 180 days, how many days can we anticipate that the teacher on bus duty will likely have CPR certification?

45% of the time

0.45 multiplied by 180 results in 81 days

In approximately 81 days, it is likely that the teacher on bus duty will be certified in CPR

7 0
2 months ago
A bouncing ball reaches a height of 27 feet at its first peak, 18 feet at its second peak, and 12 feet at its third peak. Descri
tester [12383]
A geometric sequence models the bounce heights:
Use the formula
A (subscript n) = Ar(n-1)
a = the first-term value
n = the index of the term you want (for the fourth peak, n = 4) 
r = common ratio, found by dividing the second term by the first
Here r = 18/27 = 2/3 because 27×(2/3) = 18, and similarly 18×(2/3) = 12
For the fourth peak n = 4
Compute: 4th term = 27(2/3)^(4-1) = 8
Therefore the height at the fourth peak is 8
4 0
3 months ago
Read 2 more answers
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