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insens350
1 month ago
9

Makayla is taking a math course and is working with the perimeter of rectangles. She knows the perimeter and length of her recta

ngle but wants to solve for the width. Rearrange the following equation for W, where P is the perimeter, L is the length, and W is the width of the rectangle. P = 2L + 2W.
A. W = 2p − 2l
B. W = p/ 2-2 times l
C. W = the quantity p + 2 times l/2
D. W = 2p + 2l
Mathematics
1 answer:
lawyer [12.5K]1 month ago
5 0

Answer:

  W=\dfrac{P}{2}-L

Step-by-step explanation:

  P=2L+2W \qquad\text{given}\\\\P-2L=2W \qquad\text{subtract $2L$}\\\\\dfrac{P-2L}{2}=W \qquad\text{divide by 2}\\\\W=\dfrac{P}{2}-L \qquad\text{carry out the division}

The given formula doesn't appear to match any of the answer choices.

  W = (P/2) - L

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Given matrix A below, and that A = B, find the value of the elements in B. A = 9 −2 3 2 17 0 3 22 8 b11 = b12 = b13 = b21 = b22
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Answer:

b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8

Step-by-step explanation:

Review the provided matrix

A=\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]

Let matrix B be defined as

B=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

It is stated that

A=B

\left[\begin{array}{ccc}9&-2&3\\2&17&0\\3&22&8\end{array}\right]=\left[\begin{array}{ccc}b_{11}&b_{12}&b_{13}\\b_{21}&b_{22}&b_{23}\\b_{31}&b_{32}&b_{33}\end{array}\right]

By comparing the corresponding elements from both matrices, we derive

b_{11}=9,b_{12}=-2,b_{13}=3

b_{21}=2,b_{22}=17,b_{23}=0

b_{31}=3,b_{32}=22,b_{33}=8

Consequently, the needed values are b_{11}=9,b_{12}=-2,b_{13}=3,b_{21}=2,b_{22}=17,b_{23}=0,b_{31}=3,b_{32}=22,b_{33}=8.

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2 months ago
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