If (a^3+27)=(a+3)(a^2+ma+9) then m equals

Answer:

The cabin is located 567 yards away.

Step-by-step solution:

The bearing angle of 21.2° corresponds to the interior angle near the cabin in the triangle.

Apply the tangent function:

Opposite side length: 220 yards

Adjacent side length: x (distance to cabin)

tan(21.2°) = opposite / adjacent

tan(21.2°) = 220 yards / x

Multiply both sides by x:

x × tan(21.2°) = 220 yards

Isolate x:

x = 220 yards / tan(21.2°)

x = 220 / 0.388

x = 567 yards

Hence, the cabin is 567 yards away.

Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Since RS is parallel to DC, we conclude that;

∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that  ΔBCD ~ ΔBSR, we obtain;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).

Quadratic equations find their application in various real-world scenarios such as: sports, bridges, projectile motion, the curvature of bananas, and so on.

Here are three images representing real-world instances of quadratics:

Example 1: A cyclist travels along a parabolic trajectory to leap over obstacles.

Example 2: A person throws a basketball towards the hoop, moving in a gently upward path described by a quadratic curve.

Example 3: A football player kicks the ball upward, which follows a quadratic path as it travels a distance.

Answer:

D

Step-by-step explanation:

You should insert the provided x and y coordinates into the equations to determine which one satisfies both points.

D is valid for both:

5 = 5/4(4)

0 = 5/4(0)