Jai Narayan sells two radio sets for 2288 each.

Answer:

The three errors are:

1) Incorrectly swapping the variables x and y.

2) Failure to use the ± symbol.

3) The domain is wrong; it should be x ≤ 0.

Step-by-step explanation:

Review the following steps.

Step 1:

The initial step is incorrect because the variables x and y were switched improperly; it should be:

Step 2:

Step 3:

Step 4: , for x ≥ 0

Step 4 contains an error as the ± sign is required. Additionally, the function's domain is inaccurately stated.

The radicand must be nonnegative, implying that x must satisfy x ≤ 0.

Step One

Deduct 32 from both sides.

F - 32 = \frac{9}{5}(k - 273.15)

Step Two

Multiply each side by \frac{5}{9}.

\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)

\frac{5}{9}(F - 32) = k - 273.15

Step Three

Add 273.15 to both sides.

\frac{5}{9}(F - 32) + 273.15 = k

Problem B

F = 180

Solve for k

k = \frac{5}{9}(F - 32) + 273.15

k = \frac{5}{9}(180 - 32) + 273.15

k = \frac{5}{9} \times 148 + 273.15

k = 82.2222 + 273.15

k = 355.3722

k = 355.4  <<< Answer

what was the response

Solution:

We know, g(x) = f(x) + k --------(1)

It is given that f(x) = (x+2)

and g(x) = (x+5)

Substituting f(x) and g(x) into equation (1):

→ (x+5) = (x+2) + k

→ = k

→ k =

Thus, the value of k is 1.