The circled portion of DNA in the following picture is

Question from alternative source

Numerous mutation types can arise in the body. Cystic fibrosis is a genetic condition attributed to various mutations in the CFTR gene. A specific mutation in the CFTR gene related to cystic fibrosis results in an earlier-than-expected termination of translation in the gene sequence. Which kind of mutation leads to this translation error resulting in cystic fibrosis?

• silent
• missense
• nonsense
• deletion

Answer:

Nonsense

Explanation:

Nonsense mutations refer to those that create a premature stop codon. The stop codons include UAG, UAA, and UGA. This situation could occur if a nucleotide substitution happens in the mRNA codon UAC (which codes for the amino acid Tyrosine) changing to UAG (which signifies a stop codon).

Upon reaching this codon, the translation machinery would interpret it as a directive to end translation. Consequently, the mRNA would be released, leading to a truncated version of the amino acid, which is likely not functional and could be flagged for destruction by the cell.

The key to your inquiry is the duration and its impact on each material, along with the understanding that nitrogen remains unchanged as it is an unalterable variable. Meanwhile, all other aspects, such as time, the substance under investigation, and the potential for nodule formation can vary without altering the fundamental nature of the experiment; otherwise, you would be dealing with a dependent variable. I hope this clarifies your question:-)

Answer:

A total of 5.5 liters of blood is present

Therefore, to achieve a blood alcohol content (BAC) that surpasses 0.1 gram per 100 ml, a total of 0.1/100 × 5500 = 5.5 grams of alcohol is required.

1 oz equals 28.3 grams

28.3 grams of water equal 28.3 ml

It has an alcohol content of 20 percent by volume,

So, the amount of alcohol in one drink would be:

20/100 × 28.3

= 5.66 ml

= 5.66 × 0.79 (density of ethanol)

= 4.47 grams

Thus, the total number of drinks required will be 5.5 g / 4.47 g = 1.2

Hence, 1.2 drinks would elevate the BAC to over 0.1 g / 100 ml in the bloodstream.