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LUCKY_DIMON
27 days ago
14

The average 70 kg (150 lb) being has 5.5 L of blood (1.05 g/mL). How many 1 oz drinks of 20% alcohol by volume (40 proof) must b

e consumed for the blood alcohol content (BAC) to exceed 0.1 (BAC is g alcohol per 100 mL blood)? Assume that all of the alcohol consumed goes directly into the blood.
Biology
1 answer:
garik1379 [2K]27 days ago
4 0

Answer:

A total of 5.5 liters of blood is present

Therefore, to achieve a blood alcohol content (BAC) that surpasses 0.1 gram per 100 ml, a total of 0.1/100 × 5500 = 5.5 grams of alcohol is required.

1 oz equals 28.3 grams

28.3 grams of water equal 28.3 ml

It has an alcohol content of 20 percent by volume,

So, the amount of alcohol in one drink would be:

20/100 × 28.3

= 5.66 ml

= 5.66 × 0.79 (density of ethanol)

= 4.47 grams

Thus, the total number of drinks required will be 5.5 g / 4.47 g = 1.2

Hence, 1.2 drinks would elevate the BAC to over 0.1 g / 100 ml in the bloodstream.

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