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24 days ago

13

Multiply each element in origList with the corresponding value in offsetAmount. Print each product followed by a space.Ex: If or

igList = {4, 5, 10, 12} and offsetAmount = {2, 4, 7, 3}, print:8 20 70 36 import java.util.Scanner;public class VectorElementOperations {public static void main (String [] args) {final int NUM_VALS = 4;int[] origList = new int[NUM_VALS];int[] offsetAmount = new int[NUM_VALS];int i;origList[0] = 20;origList[1] = 30;origList[2] = 40;origList[3] = 50;offsetAmount[0] = 4;offsetAmount[1] = 6;offsetAmount[2] = 2;offsetAmount[3] = 8;/* Your solution goes here */System.out.println("");}}

1 answer:

Kisachek [217]24 days ago

8 0

Answer:

Here is the JAVA program:

import java.util.Scanner; // to take input from user

public class VectorElementOperations {

public static void main(String[] args) {

final int NUM_VALS = 4; // size is fixed to 4 assigned to NUM_VALS

int[] origList = new int[NUM_VALS];

int[] offsetAmount = new int[NUM_VALS];

int i;

//two arrays origList[] and offsetAmount[] get assigned their values

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 4;

offsetAmount[1] = 6;

offsetAmount[2] = 2;

offsetAmount[3] = 8;

String product=""; // variable for storing the product results

for(i = 0; i <= origList.length - 1; i++){

/* iterates from 0 to the end of origList */

/* multiplies each origList entry with the corresponding offsetAmount entry, stores results in product */

product+= Integer.toString(origList[i] *= offsetAmount[i]) + " "; }

System.out.println(product); }}

Output:

80 180 80 400

Explanation:

If you wish to print the product of origList alongside offsetAmount values vertically, this can be done in this manner:

import java.util.Scanner;

public class VectorElementOperations {

public static void main(String[] args) {

final int NUM_VALS = 4;

int[] origList = new int[NUM_VALS];

int[] offsetAmount = new int[NUM_VALS];

int i;

origList[0] = 20;

origList[1] = 30;

origList[2] = 40;

origList[3] = 50;

offsetAmount[0] = 4;

offsetAmount[1] = 6;

offsetAmount[2] = 2;

offsetAmount[3] = 8;

for(i = 0; i <= origList.length - 1; i++){

origList[i] *= offsetAmount[i];

System.out.println(origList[i]);}

}}

Output:

80

180

80

400

The program is shown with the output as a screenshot along with the example's input.

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A subway car leaves station A; it gains speed at the rate of 4 ft/s^2 for of until it has reached and then at the rate 6 then th

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Answer:

Refer to the attached document

1512 ft

Explanation:

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A negative acceleration shows the area lies below the t-axis, indicating a decrease in speed.

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Since acceleration remains constant or zero, the v−t graph is made up of linear segments connecting the calculated points.

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6 < t < 10: x10 - x6 = 0.5*4*(24 + 48) = 144 ft

10 < t < 34: x34 - x10 = 48*24 = 1152 ft

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Response:

00100111

Explanation:

We have been given;

10010110

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Add them following standard binary addition rules

10010110

10010000

-------------

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Answer:

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