A cylinder in space is of uniform temperature and dissipates 100 Watts. The cylinder diameter is 3" and its height is 12". Assum

Response:

1) g=31.87ft/s^2

2)m=120

W=119.64lbf

Clarification:

initial segment

the weight of an object with a specified mass is determined using the equation

W=mg

we need to convert 120lb into slug

m=120lbx1slug/32.147lb=3.733slug

calculating for g

g=W/m

g=119/3.733=31.87ft/s^2

subsequent segment

the mass remains unchanged

m=120lb=3.733slug

Weight

W=3.733slug*32.05ft/s^2=119.64lbf

Answer:

90 L.atm

Explanation:

According to the provided details:

First pathway:

A( 3 atm, 20 L) → C ( 1 atm, 20 L) → D (1 atm, 50 L)

Second pathway:

A(3 atm, 20 L) → B( 3 atm, 50 L) → D ( 1 atm, 50 L)

As the number of moles is 1.00 moles

To calculate wAB;

A → B signifies the transformation is happening at a steady pressure;

Thus,

wAB = pressure multiplied by the change in volume

wAB = P(V₂ - V₁)

wAB = 3 atm (50 L - 20 L)

wAB = 3 atm (30 L)

wAB = 90 L.atm

Answer:

a) q = 7671 W

T0 = 47.6°C

b) ΔP = 202.3 N/m²

P = 58.2 W

c) hDarray = 2 times hD of an isolated element.

Explanation:

see the image for the solution.

Answer:

Change in length = 0.0913 in

Explanation:

Given data:

Length = 6 ft

Diameter = 0.2 in

Load w = 200 lb/ft

Solution:

We start by applying the equilibrium moment about point C, expressed as

∑M(c) = 0.............1

This can be used to find the force in AB.

10× 200 × ( 5) - (T cos(30)) × 10 = 0

Solving gives us

Tension in wire T(AB) = 1154.7 lb

We also know the modulus of elasticity for A992 is

E = 29000 ksi

And the area will be

Area =

The change in length is expressed as

Change in length = .........2

Substituting values results in

Change in length =

Change in length = 0.0913 in