Answer:
- 128 Superscript StartFraction 3 Over x EndFraction
- (4RootIndex 3 StartRoot 2 EndRoot)x
- (4 (2 Superscript one-third Baseline) ) Superscript x
Step-by-step explanation:
Considerando la ecuación dada ![(\sqrt[3]{128} )^{x}\\](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C)
De acuerdo con una de las leyes de índices,
![(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}](https://tex.z-dn.net/?f=%28%5Csqrt%5Ba%5D%7Bm%7D%20%29%5E%7Bb%7D%5C%5C%3D%20%28%5Csqrt%7Bm%7D%29%5E%5Cfrac%7Bb%7D%7Ba%7D)
Aplicando esta ley a la pregunta;
![(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C%20%3D%20%7B128%7D%20%5E%5Cfrac%7Bx%7D%7B3%7D%5C%5C%20%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B64%2A2%7D%29%5E%7Bx%7D%20%5C%5C%20%3D%20%284%5Csqrt%5B3%5D%7B2%7D%29%5E%7Bx%7D%20%5C%5C%3D%20%284%282%5E%7B1%2F3%7D%20%29%5E%7Bx%7D%20%29)
<pLos siguientes son ciertos de acuerdo con el cálculo presentado
128 Superscript StartFraction 3 Over x EndFraction
(4RootIndex 3 StartRoot 2 EndRoot)x
(4 (2 Superscript one-third Baseline) ) Superscript x
To obtain a complete response, the diagram would be essential. However, to approximate the solution, I'd calculate the distances from her home to her school and combine that with the stretch from school to work, and finally, from work back home. If there’s no information regarding the distance from work to home, I’d simply double the traveled distance already accounted for.
The reasoning follows that both angles are 90 degrees.
The findings are probably not valid since it is improbable that the tires fitted in just one hour on Monday accurately reflect the whole population of tires.Step-by-step explanation: Out of 8 hours, do you truly believe that one hour could stand for all? This is the reason the results are likely invalid (I also participated in the quiz).
Answer:
45 millas.
Explicación paso a paso:
Dado que la:
Distancia total recorrida = 390 millas
Tiempo total = 8 horas
Designando la distancia recorrida por la vía local como L
y la distancia recorrida por la carretera como H
Por la vía local,
La Velocidad = distancia/ tiempo
20 = L / T
T = L /20.... (1)
Por la carretera,
Distancia recorrida H = 390 - L
Sea el tiempo = t
La Velocidad = distancia/tiempo
60 = (390 - L)/t
t = ( 390 - L)/60
Pero el tiempo total = T + t
<pEs decir
8 = L/20 + (390 - L)/60
<pEl MCM en el lado derecho sería 60<p8 = ( 3L + 390 - L )/60<pMultiplicamos en cruz
480 = 2L + 390
<pAgrupamos los términos semejantes
2L = 480 - 390
2L = 90
L = 90/2
L = 45 millas.
<pAsí que la distancia que Minato recorrió por vías locales es de 45 millas
