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melamori03
15 days ago
5

Which of these equations have no solution? Check all that apply. 2(x + 2) + 2 = 2(x + 3) + 1 2x + 3(x + 5) = 5(x – 3) 4(x + 3) =

x + 12 4 – (2x + 5) = (–4x – 2) 5(x + 4) – x = 4(x + 5) – 1
Mathematics
2 answers:
Inessa [3.9K]15 days ago
8 0

Answer:

2(x + 2) + 2 = 2(x + 3) + 1

2x + 3(x + 5) = 5(x - 3)

5(x + 4) - x = 4(x + 5) - 1

Step-by-step explanation:

Inessa [3.9K]15 days ago
3 0

Answer:

  • 2(x + 2) + 2 = 2(x + 3) + 1
  • 2x + 3(x + 5) = 5(x – 3)
  • 5(x + 4) – x = 4(x + 5) – 1

Step-by-step explanation:

To identify solutions, subtract the right side from both sides and simplify.

1. For 2(x + 2) + 2 = 2(x + 3) + 1

   Subtract right side: 2(x + 2) + 2 - (2(x + 3) + 1) = 0

   Simplify: 2x + 4 + 2 - 2x - 6 - 1 = 0

   Which results in -1 = 0, meaning no solutions.

__

2. For 2x + 3(x + 5) = 5(x – 3)

   Subtract right side: 2x + 3(x + 5) - 5(x – 3) = 0

   Simplify: 2x + 3x + 15 - 5x + 15 = 0

   This leads to 30 = 0, no solutions again.

__

3. Equation 4(x + 3) = x + 12

   Subtract right side: 4(x + 3) - (x + 12) = 0

   Simplify: 4x + 12 - x - 12 = 0

   Equals 3x = 0, so one solution: x = 0.

__

4. Equation 4 – (2x + 5) = (–4x – 2)

   Subtract right side: 4 – (2x + 5) - (–4x – 2) = 0

   Simplify: 4 - 2x - 5 + 4x + 2 = 0

   Gives 2x + 1 = 0, meaning one solution: x = -1/2.

__

5. Equation 5(x + 4) – x = 4(x + 5) – 1

   Subtract right side: 5(x + 4) – x - (4(x + 5) – 1) = 0

   Simplify: 5x + 20 - x - 4x - 20 + 1 = 0

   Results in 1 = 0, no solution here.

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