The average diameter of sand dollars on a certain island is 5.00 centimeters with a standard deviation of 0.90 centimeters. If 1

Question

16 days ago

5

The average diameter of sand dollars on a certain island is 5.00 centimeters with a standard deviation of 0.90 centimeters. If 1

6 sand dollars are chosen at random for a collection, find the probability that the average diameter of those sand dollars is more than 4.73 centimeters. Assume that the variable is normally distributed.

Mathematics

1 answer:

Inessa [8.9K] · Answer 1 · 2026-03-11T14:46:06+03:00

Answer:

The likelihood that the average diameter of these sand dollars exceeds 4.73 centimeters is 0.5910

Step-by-step explanation:

Provided data:

mean, x = 5

standard deviation, σ = 0.9

sample size, n = 16

We will determine the probability of the average diameter of the sand dollars being greater than 4.73 centimeters.

P(x>4.73) = P(z > (4.73 - x) / (σ $\sqrt{n}$ )

= P(z > (4.73 - 4) / (0.9 $\sqrt{16}$ )

= P(z > 0.203)

= 0.5910