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gregori
11 days ago
13

Alonso went to the market with \$55$55dollar sign, 55 to buy eggs and sugar. He knows he needs a package of 121212 eggs that cos

ts \$2.75$2.75dollar sign, 2, point, 75. After getting the eggs, he wants to buy as much sugar as he can with his remaining money. The sugar he likes comes in boxes that each cost \$11.50$11.50dollar sign, 11, point, 50.
Mathematics
1 answer:
Svet_ta [4.3K]11 days ago
7 0

Answer:

2.75 + 11.50S\leq55

4

Step-by-step explanation:

You might be interested in
In ΔHIJ, the measure of ∠J=90°, JI = 4, HJ = 3, and IH = 5. What ratio represents the tangent of ∠I?
Inessa [3926]

Answer:

The ratio  \frac{3}{4} corresponds to the tangent of ∠I.

Step-by-step explanation:

Let’s revisit the trigonometric ratios:

  • sin Ф =  \frac{opposite}{hypotenuse}
  • cos Ф =  \frac{adjacent}{hypotenuse}
  • tan Ф =  \frac{opposite}{adjacent}

For triangle HIJ

∵ m∠J = 90°

- The hypotenuse is the side opposite the right angle.

So, HI is the hypotenuse.

∵ HJ = 3 units

∵ IH = 5 units

- We’ll apply the Pythagorean Theorem to solve for HJ.

∵ (HJ)² + (IJ)² = (IH)²

∴ 3² + (IJ)² = 5²

∴ 9 + (IJ)² = 25

- Subtract 9 from both sides.

∴ (IJ)² = 16

- Taking the square root on both sides gives:

∴ IJ = 4 units

To determine the tangent of ∠I, identify the sides that are opposite and adjacent to it.

∵ HJ is opposite to ∠I

∵ IJ is adjacent to ∠I

- Utilizing the rule of tan above:

∴ tan(∠I) = \frac{HJ}{IJ}

∴ tan(∠I) = \frac{3}{4}

The ratio \frac{3}{4} indicates the tangent of ∠I.

7 0
10 days ago
All of the students in Ms. Osbourne's class like pizza. Jeff is a student who likes pizza. Therefore, Jeff is a student in Ms. O
Zina [3917]
Hindi ito palaging totoo.


4 0
13 days ago
Read 2 more answers
Which shows one way to determine the factors of 4x3 + x2 – 8x – 2 by grouping?
Leona [4187]

Keep in mind that when factoring by grouping, we should divide the expression into two pairs that share some commonality. The goal is to create a common binomial factor after we factor each pair. It's important to mention that there can be multiple ways to pair the factors.

Let's explore the method of finding the factors of our expression through grouping:

Step 1. Identify shared multiples among the terms.

We can see that 4 and 8 are multiples of 2, 8 is a multiple of 4, and all are multiples of 1, suggesting various pairing options.

Step 2. Identify common variables.

Typically, we should pair variables that have the highest exponents to ensure that when factoring each group, we derive another common binomial factor.

Step 3. Factor each group; if it leads to another common binomial factor, you did it correctly. If it doesn't, try again.

Let's use these steps on our expression 4x^3+x^2-8x-2

For step 1, we are grouping 4x^3 and -8x. Don't forget to pair the leftover factors too.

(4x^3-8x)+(x^2-2)

The common factor for the first group is 4x, which we will factor out.

4x(x^2-2)+(x^2-2)

Look at that! We obtained the common binomial factor (x^2-2). Sadly, 4x(x^2-2)+(x^2-2) isn't among our provided choices, so we'll attempt this again:

This time, let's group the higher variables from step 2: 4x^3 and x^2

4x^3+x^2-8x-2

(4x^3+x^2)+(-8x-2)

The common factor in the first group turns out to be x^2, and in the second one, it's -2, so we'll factor both of them out:

(4x^3+x^2)+(-8x-2)

x^2(4x+1)-2(4x+1)

Now, we have chosen option A.

Therefore, we can conclude that the correct answer is: A) x2(4x + 1) – 2(4x + 1)

3 0
11 days ago
Which of these equations have no solution? Check all that apply. 2(x + 2) + 2 = 2(x + 3) + 1 2x + 3(x + 5) = 5(x – 3) 4(x + 3) =
Inessa [3926]

Answer:

  • 2(x + 2) + 2 = 2(x + 3) + 1
  • 2x + 3(x + 5) = 5(x – 3)
  • 5(x + 4) – x = 4(x + 5) – 1

Step-by-step explanation:

To identify solutions, subtract the right side from both sides and simplify.

1. For 2(x + 2) + 2 = 2(x + 3) + 1

   Subtract right side: 2(x + 2) + 2 - (2(x + 3) + 1) = 0

   Simplify: 2x + 4 + 2 - 2x - 6 - 1 = 0

   Which results in -1 = 0, meaning no solutions.

__

2. For 2x + 3(x + 5) = 5(x – 3)

   Subtract right side: 2x + 3(x + 5) - 5(x – 3) = 0

   Simplify: 2x + 3x + 15 - 5x + 15 = 0

   This leads to 30 = 0, no solutions again.

__

3. Equation 4(x + 3) = x + 12

   Subtract right side: 4(x + 3) - (x + 12) = 0

   Simplify: 4x + 12 - x - 12 = 0

   Equals 3x = 0, so one solution: x = 0.

__

4. Equation 4 – (2x + 5) = (–4x – 2)

   Subtract right side: 4 – (2x + 5) - (–4x – 2) = 0

   Simplify: 4 - 2x - 5 + 4x + 2 = 0

   Gives 2x + 1 = 0, meaning one solution: x = -1/2.

__

5. Equation 5(x + 4) – x = 4(x + 5) – 1

   Subtract right side: 5(x + 4) – x - (4(x + 5) – 1) = 0

   Simplify: 5x + 20 - x - 4x - 20 + 1 = 0

   Results in 1 = 0, no solution here.

3 0
15 days ago
Read 2 more answers
The combined area of two squares is 45 square centimeters. Each side of one square is twice as long as a side of the other squar
Leona [4187]

Let the length of one square be x. Area will be x*x = x².

Thus, the second square's side length is 2x, leading to an area of 2x*2x = 4x².

The total area combined is x² + 4x² = 5x².

This total area equals 45 cm².

Hence, 5x² = 45. Dividing each side by 5 results in
x² = 45/5, so
x² = 9. By taking the square root of both sides, we find
x = √9, which gives
x = 3.

Consequently, the length of the larger square is 2x, which equals 2*3 = 6 cm.
The length of the larger square is 6cm.

7 0
2 days ago
Read 2 more answers
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